Questions About Reciprocal Lattice Edge Length

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SUMMARY

The edge length of a reciprocal lattice for a body-centered cubic (BCC) structure, which corresponds to a face-centered cubic (FCC) lattice, is calculated as 4π/a, contrary to the expected 2π/a. This discrepancy arises from the Fourier transform of the lattice, which accounts for both positive and negative values, effectively doubling the length. The highest spatial frequency in the reciprocal lattice dictates this calculation, confirming that the total length is indeed 4π/a.

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  • Understanding of reciprocal lattice concepts
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  • Knowledge of body-centered cubic (BCC) and face-centered cubic (FCC) structures
  • Basic principles of lattice vectors and their significance
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Students and researchers in solid-state physics, crystallographers, and materials scientists who are studying the properties of reciprocal lattices and their applications in material characterization.

lemonxx
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TL;DR
Reciprocal Lattice Edge Length
Hi. So, i am currently studying reciprocal lattices, and am not quite sure how to find the edge length of a reciprocal lattice. for example I had expected the RL of BCC, which is FCC, to have edge lengths 2pi/a but it turns out it is 4pi/a, how come?
 
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lemonxx said:
TL;DR Summary: Reciprocal Lattice Edge Length

Hi. So, i am currently studying reciprocal lattices, and am not quite sure how to find the edge length of a reciprocal lattice. for example I had expected the RL of BCC, which is FCC, to have edge lengths 2pi/a but it turns out it is 4pi/a, how come?
I'm going back a long time here but iirc, the reciprocal lattice will have a side length corresponding to the highest spatial frequency. So that would suggest 2π/a but the Fourier transform will give positive and negative values so you get both signs of the reciprocal length, which is a total length of +2π/a to -2π/a, which gives twice the length =4π/a
The first row of this diagram (from the Wiki page) seems to confirm my idea.
1734889435789.png

As no one has answered you yet, this may be enough for you but I could be corrected by a ton of knowledge from elsewhere.
 

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