Quick 2D Motion Question (wind resistance)

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Vroc
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Homework Statement


An airplane is flying 100m/s (N20E) according to the pilot, but is in a wind that is blowing 40 m/s (S10E). What is the plane's real velocity?


Homework Equations


Pythagorean Therom
Cosin and Sin Laws
Component Method


The Attempt at a Solution



Okay, I think I can easily get the answer if I know what this question is asking me. By real velocity, Does it mean the displacement from point 100 m/s (N20E) to 40 m/s (S20E)? Like, I can draw it on a graph and make the triangle. I would then calculate the angle and length of the unknown side. If that's not it, Then how would I go about getting it? Please Help me understand this.
 
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Hi Vroc! :smile:
Vroc said:
An airplane is flying 100m/s (N20E) according to the pilot …

Okay, I think I can easily get the answer if I know what this question is asking me.

It means the velocity Vpa of the plane relative to the air is 100 m/s (N20E)

you're given Vag, the velocity of the air relative to the ground,

and you need to find Vpg, the velocity of the plane relative to the ground. :wink:
 
tiny-tim said:
Hi Vroc! :smile:


It means the velocity Vpa of the plane relative to the air is 100 m/s (N20E)

you're given Vag, the velocity of the air relative to the ground,

and you need to find Vpg, the velocity of the plane relative to the ground. :wink:

What? I just need to know what formula to use or how I can use my graph to find the answer.
I'm given the planes Velocity (100m/s n20e) and than the wind (40 m/s s10e)
 
Vroc said:
I'm given the planes Velocity (100m/s n20e)

no, that's not the plane's velocity (relative to the ground), it's the plane's velocity relative to the air

now use vector addition
 
tiny-tim said:
no, that's not the plane's velocity (relative to the ground), it's the plane's velocity relative to the air

now use vector addition

Okay, If I can use vector addiction, than I can do it the way I mentioned earlier by making a triangle and finding the unknown side and angle because they both are ways of finding the same thing. correct?
 
Vroc said:
Okay, If I can use vector addiction, than I can do it the way I mentioned earlier by making a triangle and finding the unknown side and angle because they both are ways of finding the same thing. correct?

correct :smile:

(and make sure your vector triangle has the arrows the right way round,

so that Vpg = Vpa + Vag :wink:)
 
tiny-tim said:
correct :smile:

(and make sure your vector triangle has the arrows the right way round,

so that Vpg = Vpa + Vag :wink:)

Thank you so much.