How does the solubility of BaSO4 in a solution of Na2SO4 compare to its solubility in pure water? I said that it is greater in the water. I don't know if I'm right, or how to explain it however. I see that if those two compounds reacted, then the products would be the exact same as the reactants. Therefore there would be no dominant charges in gettting the reaction to move forward. Is this part of it, or all of it, help me out please.