Quick Hello Then Question About Energy

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The discussion revolves around calculating the time required to push a bucket with a mass of 2 kg over a distance of 5 meters, given a force of 100 N and a friction force of 10 N at an angle of 60 degrees. The correct approach involves determining the net force acting on the bucket, which is affected by the friction opposing the applied force. The net acceleration can be calculated using Newton's second law, and the time can be derived from the kinematic equations for constant acceleration. The back-of-the-book answer is confirmed to be 0.71 seconds.

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Hey,

Im A Highschool Student; Nerd In Development; lol anyways iv'e come across this question in my Text Book and I am not sure how to figgure it out; Can Someone PLEASE for the love of god tell me how the hell to do it

Ok Heres The Status They Give You:

Mass - 2kG
Angle - 60
Force - 100N
Friction Force- 10N

How long will it take to push this bucket over A Distance Of 5 Meaters?






Back Of Book Answer= 0.71s


Thanks
~Matty-Alan~
 
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Celestial_Morning said:
Hey,

Im A Highschool Student; Nerd In Development; lol anyways iv'e come across this question in my Text Book and I am not sure how to figgure it out; Can Someone PLEASE for the love of god tell me how the hell to do it

Ok Heres The Status They Give You:

Mass - 2kG
Angle - 60
Force - 100N
Friction Force- 10N

How long will it take to push this bucket over A Distance Of 5 Meaters?

One should show one's work first.

Well, one needs to know the initial velocity, which may = 0 here.

If there is a net acceleration, then the block is accelerating.

The net acceleration is simply the net force divided by mass.

Now, if one pushes the block, then friction opposes the pushing, i.e. the friction force is in the opposite direction of the pushing force.

As for the pushing force, one must determine the component parallel with the displacement of 5 meters (presumably horizontal, but that is not given in the problem statement). Furthermore, with respect to the angle of 60°, it is not stated whether that is with respect of vertical or horizontal. And does the friction force of 10N apply simply to the mass of the block, or to the block plus whatever downward force one applies to the block.

Then think of the equation which describes displacement as a function of time for constant acceleration. Hint, it is a quadratic relationship.

This might help - http://hyperphysics.phy-astr.gsu.edu/Hbase/mot.html#mot1
 
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