Quick question about a simple perturbation theory question

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SUMMARY

The discussion centers on applying perturbation theory to calculate the first-order shift in the ground state energy of a charged particle in a harmonic oscillator potential. The potential is defined as V0 = 0.5m(wx)^2, with a perturbation dV = 0.5sm(wx)^2. The key equation used is E0' - E0 = <0|h|0>, where the user expresses confusion regarding the role of charge q in the Hamiltonian. It is established that the charge should be considered in the context of the potential energy, specifically as q times the potential V.

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Homework Statement


A particle of charge q and mass m is in a harmonic oscillator potential V0=0.5m(wx)^2. A perturbation is introduced which changes the potential to V=V0 + dV with dV=0.5sm(wx)^2 where s is small.

Use perturbation theory to compute the first order shift in the ground state energy.


Homework Equations


E0' - E0 = <0|h|0>


The Attempt at a Solution


Well I've done it ish but am kind of confused about where the q is supposed to be used. Should I multiply V0 by q to get the potential energy, and use that in H?

I'm used to the hamiltonian for a SHO just having 0.5m(wx)^2 as the potential term.

Thanks
 
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Energy is charge times electric field, so q times V is energy.
 

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