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Quick question about a simple perturbation theory question

  • Thread starter joker_900
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Homework Statement


A particle of charge q and mass m is in a harmonic oscillator potential V0=0.5m(wx)^2. A perturbation is introduced which changes the potential to V=V0 + dV with dV=0.5sm(wx)^2 where s is small.

Use perturbation theory to compute the first order shift in the ground state energy.


Homework Equations


E0' - E0 = <0|h|0>


The Attempt at a Solution


Well I've done it ish but am kind of confused about where the q is supposed to be used. Should I multiply V0 by q to get the potential energy, and use that in H?

I'm used to the hamiltonian for a SHO just having 0.5m(wx)^2 as the potential term.

Thanks
 

Answers and Replies

  • #2
malawi_glenn
Science Advisor
Homework Helper
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Energy is charge times electric field, so q times V is energy.
 

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