Quick Question Cons. Energy, elastic collision, projectile

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Homework Help Overview

The problem involves a cube sliding down a frictionless incline and colliding elastically with another cube of half its mass. The scenario includes considerations of conservation of energy, momentum, and projectile motion, with specific dimensions provided for the incline and height of the table.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to clarify the use of mass in the calculations, questioning whether to use specific numerical values or symbolic representations. Some participants suggest using symbolic notation to simplify the problem, while others share their experiences with numerical values yielding correct results.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to representing mass in the problem. There is a mix of opinions on the best method to use, with some guidance offered on the benefits of symbolic representation.

Contextual Notes

Participants note that the actual values of the masses may not be necessary for the final calculations, indicating a focus on understanding the underlying principles rather than just numerical solutions.

0338jw
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Homework Statement



In a physics lab a cube slides down a frictionless incline and elastically strikes another cube at the bottom that is only half it's mass. If the incline is 30 cm high and the table is 90 cm off the floor where does each cube land?

Homework Equations


mgh=1/2mv^2
v=at+v_o
x=.5at^2 +v_o*t +x_0
conservation of momentum/energy

The Attempt at a Solution


I know that this problem has three parts, conservation of energy, collision and projectile but I had a question about the mass. so I simply use 2m and M or can i substitute any value in as long as it;s twice the value of the smaller block? I know how to solve all parts but this first part stumbled me a little bit. Thanks in advance, all help is appreciated!
 
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Don't use numerical values. Call the masses m and m/2. (Or something equivalent.)

Since the actual values of the masses are not needed, the masses will drop out of any final calculation.
 
well I used numerical values, and I still got the right answer, but thanks for the advice regardless! The big block lands .35m away and the smaller one flies 1.4m away from the table.
 
0338jw said:
well I used numerical values, and I still got the right answer, but thanks for the advice regardless!
Of course you can plug in numbers, but it's much better--and easier!--to set the equations up symbolically and understand why the masses cancel out.
 

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