Quick question, i think, link to problem included

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SUMMARY

The discussion centers on the calculation of charge density in a physics problem involving a charged cylinder and an outer spherical shell. The key point is that the radius used for determining charge density is that of the outer sphere, not just the charged cylinder. This is because the electric field and surface charge density are influenced by the entire configuration, including the charges on the surfaces of the outer shell, despite the net charge being zero. The surface charge density is defined as ε0E, where E represents the electric field at the surface.

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Homework Statement


http://www.physics.wisc.edu/undergrads/courses/spring09/248/HWSolutions/HW6Solutions.pdf

My question regards to part b of the problem on the 1st page.

Why is the radius to get the charge density the radius of the outer sphere and not just the radius of the cylinder that's actually charged? Like when the radius is more than the radius of the inner cylinder, that means there's no charge right so shouldn't the maximum radius be 1.5cm in this case?
 
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Although the net charge of the outer shell is zero, there are charges on its surfaces, negative on the inner surface and positive on the outer one. The surface charge density is equal to ε0E (E is the magnitude of electric field at the surface).

ehild
 

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