Quick Question on Conservation of Energy

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Homework Help Overview

The discussion revolves around the conservation of energy, specifically involving calculations related to work done by a spring and the resulting velocity of an object. The original poster presents their calculations for work and velocity, seeking validation and further assistance with additional problems.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate work done using the formula for elastic potential energy and subsequently determines velocity. They seek confirmation of their results and express a desire for help with other problems.

Discussion Status

Some participants affirm the calculations presented by the original poster, indicating that the answers look good. However, there is a suggestion to separate the additional problems into their own threads, emphasizing the importance of posting attempts for each problem.

Contextual Notes

There is an indication that participants are expected to provide attempts at solutions for each problem they post, which may influence how further questions are approached.

riseofphoenix
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Quick Question on Conservation of Energy! :(

#1.
Number1.png


For this one, I did

a) W = ½kx² = ½*410*.053² = 0.5758 J
b) V = √[2W/m] = √[2*.5758/2.00] = 0.7588 m/s

Are those right?
If so, can you help me solve Number 3 and 7 real quick!

#3.
Number3.png



#7.
Number7.png
 
Last edited:
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riseofphoenix said:
#1.
Number1.png


For this one, I did

a) W = ½kx² = ½*410*.053² = 0.5758 J
b) V = √[2W/m] = √[2*.5758/2.00] = 0.7588 m/s

Are those right?
If so, can you help me solve Number 3 and 7 real quick!
Those answers look good.

I suggest posting #3 & #7 each in its own thread.

You will also be expected to post an attempt at a solution for each.
#3.
Number3.png



#7.
Number7.png
 


I tried but no one responded...
just my luck.....
 


SammyS said:
Those answers look good.

I suggest posting #3 & #7 each in its own thread.

You will also be expected to post an attempt at a solution for each.

I tried but no one responded...
 


riseofphoenix said:
I tried but no one responded...
Did you post #3 ?
 

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