1. The problem statement, all variables and given/known data So we have 65N @ 30*, 30N @ 180* and 20N at 250* 2. Relevant equations Ncos(angle)i + Nsin(angle)j 3. The attempt at a solution Using this video I did the following. F1(65N) = 65cos(30)i+65sin30i Then using the radian circle I saw that 30* has x,y coordinates of sqrt3/2 and 1/2 respectively. So as shown in the video I did 65(root3/2)i+65(1/2)j = 56.3i + 32.5j I did this for the left one too (30N). But for the one at the bottom (20N) I get the degree of it to be 250. (270-20) = 250. 250* is not on the radian circle so how can I write 250* in terms of x,y coordinates? If we look at this radian circle. We see that 240* = (-1/2, -sqrt3/2) and then it goes to 270* = (0,-1). How can I find the x,y coordinates for 250* and use it in the equation? Thanks in advance.