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What's the quickest way to calculate the argument of $\displaystyle \pi e^{-\frac{3i\pi}{2}}$?
The quickest way to calculate the argument of the complex number $\displaystyle \pi e^{-\frac{3i\pi}{2}}$ is to recognize that it can take values of the form $-\dfrac{3\pi}{2} + 2k\pi$, where $k$ is an integer. For the principal value of the argument, select $k = 1$, resulting in an argument of $\dfrac{\pi}{2}$. The magnitude of the complex number is confirmed as $|\displaystyle \pi e^{-\frac{3i\pi}{2}}| = \pi$.
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The argument of $\displaystyle \pi e^{-\frac{3i\pi}{2}}$ can take any value of the form $-\dfrac{3\pi}2 + 2k\pi$, where $k$ is an integer. If you want the principal value of the argument then you need to choose $k$ so as to get a value in the range $(-\pi,\pi]$ (or maybe $[0,2\pi)$, depending on which definition you are using for the principal range). In this example, you would want $k = 1$, giving the principal value of the argument as $\dfrac\pi2.$Guest said:What's the quickest way to calculate the argument of $\displaystyle \pi e^{-\frac{3i\pi}{2}}$?
Thank you very much! :DOpalg said:...