Quickest way to calculate argument of a complex number

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SUMMARY

The quickest way to calculate the argument of the complex number $\displaystyle \pi e^{-\frac{3i\pi}{2}}$ is to recognize that it can take values of the form $-\dfrac{3\pi}{2} + 2k\pi$, where $k$ is an integer. For the principal value of the argument, select $k = 1$, resulting in an argument of $\dfrac{\pi}{2}$. The magnitude of the complex number is confirmed as $|\displaystyle \pi e^{-\frac{3i\pi}{2}}| = \pi$.

PREREQUISITES
  • Understanding of complex numbers and their polar representation
  • Familiarity with the concept of the argument of a complex number
  • Knowledge of principal values in trigonometric functions
  • Basic grasp of integer multiples in periodic functions
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  • Study the properties of complex numbers in polar form
  • Learn about the principal value of trigonometric functions
  • Explore the concept of periodicity in complex arguments
  • Investigate the applications of complex numbers in engineering and physics
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Mathematicians, physics students, and anyone studying complex analysis or working with complex numbers in engineering applications.

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What's the quickest way to calculate the argument of $\displaystyle \pi e^{-\frac{3i\pi}{2}}$?
 
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To be sure, I know that $|\displaystyle \pi e^{-\frac{3i\pi}{2}}| = \pi.$
 
Guest said:
What's the quickest way to calculate the argument of $\displaystyle \pi e^{-\frac{3i\pi}{2}}$?
The argument of $\displaystyle \pi e^{-\frac{3i\pi}{2}}$ can take any value of the form $-\dfrac{3\pi}2 + 2k\pi$, where $k$ is an integer. If you want the principal value of the argument then you need to choose $k$ so as to get a value in the range $(-\pi,\pi]$ (or maybe $[0,2\pi)$, depending on which definition you are using for the principal range). In this example, you would want $k = 1$, giving the principal value of the argument as $\dfrac\pi2.$
 
Opalg said:
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Thank you very much! :D
 

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