MHB Quickest way to calculate argument of a complex number

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The quickest way to calculate the argument of the complex number πe^{-3iπ/2} is to recognize that its argument can be expressed as -3π/2 + 2kπ, where k is an integer. For the principal value, k should be chosen to keep the result within the range of (-π, π] or [0, 2π), depending on the definition used. In this case, selecting k = 1 yields the principal value of the argument as π/2. The magnitude of the complex number is confirmed to be π. This method efficiently determines the argument while adhering to the principal value constraints.
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What's the quickest way to calculate the argument of $\displaystyle \pi e^{-\frac{3i\pi}{2}}$?
 
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To be sure, I know that $|\displaystyle \pi e^{-\frac{3i\pi}{2}}| = \pi.$
 
Guest said:
What's the quickest way to calculate the argument of $\displaystyle \pi e^{-\frac{3i\pi}{2}}$?
The argument of $\displaystyle \pi e^{-\frac{3i\pi}{2}}$ can take any value of the form $-\dfrac{3\pi}2 + 2k\pi$, where $k$ is an integer. If you want the principal value of the argument then you need to choose $k$ so as to get a value in the range $(-\pi,\pi]$ (or maybe $[0,2\pi)$, depending on which definition you are using for the principal range). In this example, you would want $k = 1$, giving the principal value of the argument as $\dfrac\pi2.$
 
Opalg said:
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Thank you very much! :D
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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