1. PF Contest - Win "Conquering the Physics GRE" book! Click Here to Enter
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Racecar travelling a banked curve

  1. Jul 7, 2010 #1
    1. The problem statement, all variables and given/known data

    A racecar is traveling at a speed of 120km/h on a banked curve (no friction). What is the radius of the rotation if the turn is banked at an angle of 25 degrees to the horizontal?

    2. Relevant equations

    v = 120 km/h
    angle = 25 degrees
    r = ?

    3. The attempt at a solution

    I have no idea how to approach this problem. Help? Ideas? Hints? :(
    Last edited: Jul 8, 2010
  2. jcsd
  3. Jul 7, 2010 #2
    Here's the hint: If the car were sitting on tilted track completely still, only the friction of the wheels would keep it from sliding inwards (towards the center of the circular path). What force is acting on the car in this case?

    It ought to be that this force acting on the car equals the force required to keep it on the circular path.

    The equation for centripetal force (the force required to keep an object on a circular path) is this: 6ebe58061963275ae0a62d01b654d27e.png

    where F = the force required to keep the object on a circular path, v is the velocity of the object, and r is the radius of the circular path.
  4. Jul 7, 2010 #3
    Okay, so I should use the force equation. What should I substitute for mass, as that is not given?
  5. Jul 7, 2010 #4
    There is another equation, which it is up to you to find.

    This is another equation for force will also involve mass (allowing you to cancel it out). It is an equation for the force which would cause a ball to roll to the side of a tilted track.
    Last edited: Jul 7, 2010
  6. Jul 7, 2010 #5
    Alright, here's what I have done. I didn't know how to incorporate the centripetal force formula though...

    I split Fn into two components, the vertical and the horizontal.
    Fy = force of gravity = m*g
    Fx = some force = m*a

    theta = 25 degrees

    tan25 = m*a / m*g
    - the masses cancel out
    tan25 = a / g
    tan25(g) = a
    a = 4.57 m/s^2

    a = v^2 / r
    4.57 m/s^2 = (33.3333 m/s)^2 / r
    r = 243m

    Is this right? D:
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook