How does the Radial Distribution Function compare for 1s and 2s orbitals?

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The discussion focuses on comparing the Radial Distribution Function for the 1s and 2s orbitals, emphasizing that the 1s orbital has a higher maximum electron density than the 2s orbital for any atom. Participants clarify that comparisons must be made for the same atom, specifically hydrogen, to accurately assess electron density. One user expresses confusion regarding the application of provided equations and data for solving the homework question. The importance of distinguishing between "higher maximum density" and "more density" is highlighted. Overall, the thread illustrates the challenges students face in understanding orbital electron density and the relevance of precise comparisons.
José Ricardo
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Homework Statement


Use a (simplified) graph to compare the maximum probability (electron density) of the Radial Distribution Function for the 1s and 2s orbitals.

Homework Equations


xxx

The Attempt at a Solution


H_and_He_orbitals.gif

The rest I don't how to solve.[/B]
 

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Just look at the plot - which function has a higher maximum electron density?
 
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Borek said:
Just look at the plot - which function has a higher maximum electron density?

The Helium?
 
No.

You need to compare plots for the same atom, not for different atoms.
 
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Borek said:
No.

You need to compare plots for the same atom, not for different atoms.

Ahhh... I think the hydrogen has more density for in the 1s level.
 
Am I correct now, professor?
 
I had this class, but my professor doesn't explain good. I learn more with videoclasses on Youtube than with him.
 
José Ricardo said:
Am I correct now, professor?

Don't professor me.

Yes, in _every_ atom 1s orbital has a higher maximum electron density. Note: it is important to be precise, "higher maximum density" means something else than "more density".
 
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Good mornig, Borek!
So, The data that my professor gave was:
En = -2,18 x 10-18 x (1/n²) x Z² Joules, where En is the energy from the n level, Z = atomic number.

b43d0ea3c9c025af1be9128e62a18fa74bedda2a
.v = c; Efoton = h.v; h = 6,626 x 10-34 J s; c = 3,00 x 108 m s -1;
Spectrum in the visible: 400 to 700nm

I don't know how to do this question with these data.:frown:
 
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José Ricardo said:
Good mornig, Borek!
So, The data that my professor gave was:
En = -2,18 x 10-18 x (1/n²) x Z² Joules, where En is the energy from the n level, Z = atomic number.

b43d0ea3c9c025af1be9128e62a18fa74bedda2a
.v = c; Efoton = h.v; h = 6,626 x 10-34 J s; c = 3,00 x 108 m s -1;
Spectrum in the visible: 400 to 700nm

I don't know how to do this question with these data.:frown:
I think that this question has been answered. What your professor gave you is relevant to the other thread that you started here
https://www.physicsforums.com/threads/diagram-of-energy-levels-of-hydrogen-lines.950966/
Use it there and please try to keep your threads sorted out in your mind.
 
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  • #11
Thanks, Kuruman!
 

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