Radiation in the far field for a current carrying loop

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SUMMARY

This discussion focuses on calculating the radiating fields in the far zone for a current-carrying loop of radius 'a' with a time-varying current I = Ioe-iωt'. The user employs the vector potential A(r,t) derived from the current density J(r',t') and encounters difficulties with integrals involving sinφ' and the exponential term e-ikaSinθCos(φ-φ'). The challenge arises in evaluating these integrals, which are essential for determining the radiation pattern. The assumption of low frequencies and a small loop relative to the wavelength is critical for simplifying the calculations.

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Mr. Rho
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Hi people, I have a problem with some integral here.

I have a loop of radius a, with a current I = Ioe-iωt' and trying to calculate the radiating fields in the far zone, my procedement is:

Current density: J(r',t') = Ioδ(r'-a)δ(θ'-π/2)e-iωt'/2πa2 φ (φ direction)

Here t' = t - |r-r'|/c (retarded time)

I evaluate the vector potential: A(r,t) = ∫vJ(r',t')dV/|r-r'|

I approximate 1/|r-r'| ≈ 1/r because in the far zone this term does not affect too much compared with the exponential, and |r-r'| ≈ r - aSinθCos(φ-φ') for the exponential, that plays a major role in the far zone.

The problem is that I reach integrals that I can't solve:

∫ sinφ' e-ikaSinθCos(φ-φ') dφ' for x direction

and ∫ sinφ' e-ikaSinθCos(φ-φ') dφ' for y direction (both integrals from 0 to 2π).

Maybe I'm doing something wrong, but I don't know, any help?

(r' are the source coordinates and r the observer coordinates)
 
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Usually it is assumed that you are working with low enough frequencies and a small enough loop that you can take ##a## to be small in relation to the wavelength of the radiation. Then you can approximate ##e^{-ika \sin \theta \cos (\phi - \phi ')}##.
 

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