Radiational Cooling: Calculate Net Heat Loss

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SUMMARY

The discussion focuses on calculating the net rate of heat loss due to radiational cooling, specifically addressing a scenario where a 10 m layer of atmosphere cools by 5 K over 10 hours. The correct calculation yields a net heat loss of 1.74 W m-2. Key equations referenced include the first law of thermodynamics, dq = du + pda, and the specific heat capacity equation, dq = CpdT. Participants emphasize the importance of unit consistency and clarify the use of specific heat capacity (Cp) in the calculations.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Knowledge of specific heat capacity (Cp)
  • Familiarity with units of measurement in thermodynamics
  • Basic principles of radiational cooling
NEXT STEPS
  • Study the application of the first law of thermodynamics in heat transfer scenarios
  • Learn about the calculation of radiational cooling effects in atmospheric science
  • Explore the concept of specific heat capacity and its role in thermal dynamics
  • Investigate unit conversion practices in thermodynamic equations
USEFUL FOR

Students in thermodynamics, atmospheric scientists, and engineers involved in heat transfer analysis will benefit from this discussion.

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Homework Statement


On a clear night, the loss of infrared radiation to space causes the loses 10 m of the atmosphere to cool by 5 K over 10 Hrs. Assuming a density of 1.25 kg^-3 for the air, what is the net rate of heat loss by radiational cooling, in Wm^-2 (Answer: 1.74 W m^-2)

Homework Equations


I know the first law of thermodynamics plays a role: dq = du + pda

The Attempt at a Solution


I believe the area is fixed so it will eliminate the second term leaving dq = du and du = CpdT leaving dq = CpdT. Since the net rate of heat loss is what we are looking for, it would be a change in hear over a change in time. So I have:

Cp(dT/dt) = dq/dt

then I tried to multiply the latent heat value by the (dT/dt) value to get dq but it did not provide the correct answer.
 
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"Latent heat value"? You mean CP? What value? "pda"? Check your units.
 

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