Radioactive Decay Graph in y=mx+c form

Click For Summary
SUMMARY

The discussion focuses on transforming the radioactive decay equation for lead in marine core sediments into the linear form y=mx+c. The equation provided is AL=A0e^(-λL/s), where AL represents activity at depth L, A0 is the initial activity, λ is the decay constant (0.031 yr-1), L is sediment depth, and s is the sediment accumulation rate. The transformation involves taking the natural logarithm of both sides, resulting in Ln(AL) = Ln(A0) - (λ/s)L, which aligns with the linear equation format where the slope (m) is -λ/s and the y-intercept (c) is Ln(A0).

PREREQUISITES
  • Understanding of radioactive decay principles
  • Familiarity with logarithmic functions
  • Knowledge of linear equations in the form y=mx+c
  • Basic grasp of sedimentology concepts
NEXT STEPS
  • Study the application of natural logarithms in scientific equations
  • Explore the implications of decay constants in radioactive materials
  • Research graphical representation of exponential decay
  • Learn about sediment accumulation rates and their impact on radioactivity
USEFUL FOR

Students in environmental science, geologists, and researchers analyzing radioactive decay in sedimentary contexts will benefit from this discussion.

Rockerjabroni
Messages
1
Reaction score
0

Homework Statement



This is an equation relating radioactivity of lead in marine core sediments in comparison with the depth of the sediment.

The equation is AL=A0exponential - λL/s

Where AL = activity at depth L (Bqkg-1)
Where A0 = activity at depth 0 cm (Bqkg-1)
λ = decay constant 0.031 yr-1
L= sediment depth (cm)
s= sediment accumulation rate (cmyr-1)

I need to make this into y=mx+C form


Homework Equations



As above.

The Attempt at a Solution



Well Ln both sides gives me

Ln AL = Ln (A0exponential - λL/s)

Ln AL = (Ln A0) + (Ln*exponential - λL/s) (which cancels)

Ln AL = (Ln A0) - λL/s

Ln AL = y
Ln (A0) = c
L= x
1/s = m

Is that correct? The graph has to be Ln AL against L but I wasn't sure about m and c. Thanks :)
 
Physics news on Phys.org
Hello Rockerjabroni your equation is correct.If you now compare this to y=mx+c you should see that the graph has a negative slope of gradient lambda/s and intercept lnAzero.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
6K