Calculating ln in radioactive decay

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SUMMARY

The discussion focuses on calculating the natural logarithm (ln) in the context of radioactive decay, specifically using the formula N = N0e-λt. Participants clarify that the half-life (t1/2) of a radioactive isotope is calculated using the equation t1/2 = ln(2)/λ. A user seeks assistance in calculating ln(1/2) given a count rate of 82 after 10 minutes, highlighting confusion with the application of the decay constant (λ) and the natural logarithm function.

PREREQUISITES
  • Understanding of radioactive decay principles
  • Familiarity with the natural logarithm function (ln)
  • Basic algebra for solving equations
  • Knowledge of decay constant (λ) in radioactive processes
NEXT STEPS
  • Study the derivation of the half-life formula in radioactive decay
  • Learn how to use scientific calculators for natural logarithm calculations
  • Explore the relationship between decay constant (λ) and half-life
  • Investigate applications of radioactive decay in real-world scenarios
USEFUL FOR

Students in physics or biology, particularly those studying radioactive decay, as well as educators and anyone needing to understand the mathematical principles behind decay processes.

kjevans
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Homework Statement



Radioactive decay is:

N = N0e-λt

N can also be used to describe count rate after a time, (t) where N0 is intial count rate and λ is decay constant...

Half life, t1/2 od radioactive isotope is

t1/2 = 1n2
λ

The λ should be under the ln2 but it won't let me underneath

How do I calculate 1n??

For example if time (t) in minutes is 10 and Count rate in 1 minute (N) is 82 what is 1n

I don't understand at all? Any helps is grealty appreciated

Thanks

Homework Equations



As above

The Attempt at a Solution



I found ln on the calculator but confused how I get the answer from t as and n...

I am doing as biology degree but doing a physics module which I am struggling with
 
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The equation for decay is
N = N_0 \,e^{-\lambda t}.
To find the half-life, set N = N_0/2:
<br /> \begin{align}<br /> \frac{N_0}{2} &amp;= N_0 \,e^{-\lambda t} \\<br /> \frac{1}{2} &amp;= e^{-\lambda t}.<br /> \end{align}
Now you just solve for t:
<br /> \begin{align}<br /> \ln \frac{1}{2} &amp;= -\lambda t \\<br /> t &amp;= - \frac{1}{\lambda} \ln \frac{1}{2}.<br /> \end{align}
 

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