Calculating ln in radioactive decay

kjevans
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Homework Statement



Radioactive decay is:

N = N0e-λt

N can also be used to describe count rate after a time, (t) where N0 is intial count rate and λ is decay constant...

Half life, t1/2 od radioactive isotope is

t1/2 = 1n2
λ

The λ should be under the ln2 but it won't let me underneath

How do I calculate 1n??

For example if time (t) in minutes is 10 and Count rate in 1 minute (N) is 82 what is 1n

I don't understand at all? Any helps is grealty appreciated

Thanks

Homework Equations



As above

The Attempt at a Solution



I found ln on the calculator but confused how I get the answer from t as and n...

I am doing as biology degree but doing a physics module which I am struggling with
 
The equation for decay is
[tex]N = N_0 \,e^{-\lambda t}.[/tex]
To find the half-life, set [itex]N = N_0/2[/itex]:
[tex] \begin{align}<br /> \frac{N_0}{2} &= N_0 \,e^{-\lambda t} \\<br /> \frac{1}{2} &= e^{-\lambda t}.<br /> \end{align}[/tex]
Now you just solve for [itex]t[/itex]:
[tex] \begin{align}<br /> \ln \frac{1}{2} &= -\lambda t \\<br /> t &= - \frac{1}{\lambda} \ln \frac{1}{2}.<br /> \end{align}[/tex]
 

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