Radioactive decay half-life of polonium

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Homework Help Overview

The discussion revolves around the calculation of the half-life of polonium based on its activity over a specified time period. The original poster presents a scenario where the activity of a polonium sample decreases to one-eighth of its initial value in 420 days.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the decay of activity and the concept of half-life, questioning the implications of the term "activity." There is an attempt to clarify how many half-lives correspond to a reduction to one-eighth of the original value.

Discussion Status

The discussion includes various interpretations of the problem, with participants confirming the number of half-lives needed to reach one-eighth and discussing the implications of the calculations. Some guidance is offered regarding the relationship between activity and half-life, but no consensus is reached on the final calculation.

Contextual Notes

Participants express confusion regarding the terminology used in the problem, particularly the term "activity," which may affect their understanding of the calculations involved.

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Homework Statement



c) In 420 days, the activity of a sample of polonium, Po, fell to one-eighth of its initial value. i) Calculate the half-life of polonium.

Homework Equations





The Attempt at a Solution


if the activity fell by 1/8 then it went through 4 half liefs (1/2*4=1/8) so the half life is simply 420/4=105days. The wording confuses me though because of the use of "activity" so I think what I've done might be wrong?
Thanks
 
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Half life is the time for the activity to half.
How many times do you have to cut something in half to get 1/8 of the original?
 
isnt it 4 like i said? (1/8*4=1/2)
Thanks
 
1 * 1/2 = 1/2
1/2 * 1/2 = 1/4
1/2 * 1/2 * 1/2 = 1/8
 
oops, I don't know what I was thinking. so t1/2 would be 140days?
 
correct
 
sweet, thanks
 

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