1. The problem statement, all variables and given/known data Ra (mass number 226 atomic number 88) undergoes alpha decay to form radon. If the mass of a radium nucleus is 3.753152x10-25kg, the mass of the radon nucleus is 3.686602x10-25kg and the mass of the alpha particle is 6.646322x10-27kg, find the energy released in the alpha decay in MeV. If the ratio of the mass of the products of the decay is equal to the ratio of their mass numbers, find the kinetic energy of both products after the decay charge of electron=1.6x10-19C speed of light in a vacuum=3x108ms-1 3. The attempt at a solution So for the first part I got .488MeV using the mass defect and E=mc2 (could well be wrong) but im stuck on the second part i dont understand what they are talking about ratios for?