Radioactivity and radioactive decay

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SUMMARY

The discussion focuses on calculating the remaining percentage of thorium after 266 days, given its half-life of 1.913 years. The user initially misapplied the formula by using atomic mass instead of the correct exponential decay formula, N=No*(1/2)^n. The correct calculation shows that after 266 days, which is less than one half-life, more than 50% of thorium remains. The final conclusion emphasizes the importance of using the decay formula correctly rather than relying on atomic mass for such calculations.

PREREQUISITES
  • Understanding of radioactive decay principles
  • Familiarity with half-life calculations
  • Knowledge of the decay formula N=No*(1/2)^n
  • Basic grasp of atomic mass and its significance in decay processes
NEXT STEPS
  • Study the derivation and application of the decay constant (λ) in radioactive decay
  • Learn about different types of radioactive decay, including alpha, beta, and gamma decay
  • Explore advanced decay calculations involving multiple isotopes and decay chains
  • Investigate the applications of radioactivity in fields such as medicine and energy
USEFUL FOR

This discussion is beneficial for students in nuclear physics, chemistry, and anyone studying radioactive materials, particularly those focused on decay calculations and their applications.

shigg927
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[SOLVED] Radioactivity and radioactive decay

Homework Statement


Thorium (with half-life T1/2 = 1.913 yr. and atomic mass 228.028715 u) undergoes alpha decay and produces radium (atomic mass 224.020186 u) as a daughter nucleus. (Assume the alpha particle has atomic mass 4.002603 u.)

What percent of thorium is left after 266 days?



Homework Equations



X --> Y + He
N=No*(1/2)^n
n= t/T(half)
T(half)= .693/\lambda


The Attempt at a Solution



I found that lambda=4.14x10^-5 hrs^-1 (the problem asks for it in hours, dumb, I know.)

I then found the number of half-lives to be 266 days, or 6384 hours divided by 16757.88 hours, to be .381 half-lives. I multiplied this by Thorium's atomic mass to get 36% but this keeps turning up incorrect for my online homework.
 
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Why don't you just apply N=No*(1/2)^n ?

since 266 days is shorter than the half life, more than 50% should be left.
 
Ahhhhh for some reason I thought I needed to now the number of nuclei, did NOT know I could just use the atomic mass. I got it, thank you!
 

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