Radium decomposes radioactively

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Homework Help Overview

The discussion revolves around the radioactive decomposition of radium into radon, specifically focusing on the forces involved between the radon nucleus and the emitted alpha particle. The subject area includes concepts from nuclear physics and electrostatics.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the application of Coulomb's law to calculate the force of repulsion and acceleration of the alpha particle. There are questions regarding the charges of the radon nucleus and the alpha particle, as well as uncertainty about the correct formula to use.

Discussion Status

The discussion is ongoing, with participants attempting to clarify the charges of the involved particles and the correct interpretation of Coulomb's law. Some guidance has been offered regarding looking up necessary information, but no consensus has been reached on the specific values or calculations.

Contextual Notes

Participants express uncertainty about the charges of the alpha particle and radon, indicating a need for further research on these properties. There is also confusion regarding the correct formulation of Coulomb's law.

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Radium decomposes radioactively to form radon (atomic number 86, which is also the number of protons in the nucleus) by emitting an alpha-particle from its nucleus.

The mass of an alpha-particle is 6.6404 x 10^-24 grams.

What is the force of repulsion between the radon nucleus and the alpha-particle, when the distance between them is 5 x 10^-11 cm?

What is the acceleration of the alpha-particle at this distance?

I am not sure what equation I need to use to solve this equation.

Any help would be appreciated!
 
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Try looking up Coulomb's law.
 
Coulomb's law is F = k x ((force1 x force2)/r^2)

Where k is 8.99 x 10^9

and r = distance between them which is 5 x 10^-11

I do not know how to get the force of each particle.

Some more help would be appreciated!
 
EsKiMoMoNKeY said:
Coulomb's law is F = k x ((force1 x force2)/r^2)

Where k is 8.99 x 10^9

and r = distance between them which is 5 x 10^-11

I do not know how to get the force of each particle.

Some more help would be appreciated!

No, that's not Coulomb's law. Coulombs law is
Force = k x ((charge1 x charge2)/r^2)
 
So i do not know what the alpha-particles charge is, but i can look up radon's charge right?

EDIT
So the alpha-particle's charge is the opposite of what radium loses?
 
Last edited:
Do you know what an alpha particle is? You should be able to look up its charge also.
 
The entire question was in my first post. The difference between radium to radon is 88 -> 86 so would charge 1 be 2 and charge 2 be -2?
 
No. You should know or be able to find:

(1) What is the charge on a Radon nucleus?
(2) What is an alpha particle and what is its charge?
 

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