Radius of Mercury (celestial body)

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SUMMARY

The discussion centers on calculating the radius of Mercury's orbit using its orbital period of 87.9 days and angular speed of 8.27 x 10^-7 rad/s. Participants clarify that the radius in question refers to the orbital radius, not the physical radius of the planet. They suggest utilizing Kepler's 3rd Law of planetary motion, which relates the orbital period to the radius, as a viable method to derive the radius with the given data.

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Homework Statement


It is given that the period of Mercury is 87.9 days and the angular speed of Mercury is 8.27*10^-7
I am asked to find the radius of Mercury.
I have no idea how to calculate the radius just the two pieces of information given. Should there also be the linear velocity of Mercury given in order to calculate the radius??

Homework Equations


v= r ω
ω= 2∏/T
a= v^2/r or a= r ω^2Any help would be greatly appreciated. Thank you!
 
Last edited:
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You of course mean the radius of the orbit, not of the planet.

It does seem like the question is not giving you enough data to calculate the radius using the equations provided.

However, you may be able to obtain the radius using even less information that is given(i.e., just the period). Try applying Kepler's 3rd law of planetary motion.
 

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