Radius of synchronous satellite from a planet

  • Thread starter galuda
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  • #1
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[SOLVED] radius of synchronous satellite from a planet

Homework Statement


A "synchronous" satellite, which always remains above the same point on a planet's equator, is put in orbit about a planet similar to Jupiter. This planet rotates once every 7.8h, has a mass of 1.8e27kg and a radius of 6.99e7. Given that G = 6.67e-11 calculate how far above jupiter's surface the satellite must be.


Homework Equations


Kepler's 3rd law


The Attempt at a Solution


well I converted the 7.8 hours to seconds which was 28080 seconds, then did (28080^2*g*1.8e27)/4pi^2, then took the cube root of all that. However that's not right. Any ideas?
 

Answers and Replies

  • #2
D H
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The expression you used yields the distance between the center the planet and the satellite. You were asked for the height of the satellite above the surface to the planet.
 
  • #3
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oh so I just need to subtract the planet's radius from my answer?
 
  • #4
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yes that worked thank you very much
 
  • #5
D H
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You're welcome.
 

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