Angular momentum of a satellite

[RoboNerd]

Homework Statement

A satellite is in a circular orbit of radius R from the planet's center of mass around a planet of mass M.

The angular momentum of the satellite in its orbit is:
I. directly proportional to R.
II. directly proportional to the square root of R
III. directly proportional to the square root of M.

The correct answer apparently is II and III.

Homework Equations

The Attempt at a Solution

OK, I thought that since the satellite's angular momentum is mvR * sin(90), then its angular momentum would be directly proportional to its mass, velocity, and/or even the radius orbit.

I was thus the only thing that made sense.

Why is the correct answer II and III? Thanks so much in advance for the help!

 

[drvrm]

OK, I thought that since the satellite's angular momentum is mvR * sin(90), then its angular momentum would be directly proportional to its mass, velocity, and/or even the radius orbit.

I was thus the only thing that made sense.

Why is the correct answer II and III? Thanks so much in advance for the help!

angular momentum is moment of momentum , in a way you may have correctly thought of the dependence ;
but is there a dependence of v on R?
may be v is proportional to R^ -1/2 ! then the ang. momentum can be said to be dependent on R^1/2

 

[PeroK]

The Attempt at a Solution

OK, I thought that since the satellite's angular momentum is mvR * sin(90), then its angular momentum would be directly proportional to its mass, velocity, and/or even the radius orbit.

I was thus the only thing that made sense.

Why is the correct answer II and III? Thanks so much in advance for the help!

This is a slightly nasty question because, in general, angular momentum is directly proportional to $r$ and $v$. So, if the question were:

An object is moving past a planet at a distance $R$, its angular momentum is ...? Then "proportional to R" would be correct.

But, in a circular orbit, $v$ depends on $R$ and the mass of the planet and the gravitational constant. So, it was necessary to express angular momentum in terms of all the known variables first.

The question is a bit tricky in my opinion. Slightly disengenuous, perhaps.

 

[RoboNerd]

may be v is proportional to R^ -1/2 ! then the ang. momentum can be said to be dependent on R^1/2

If I have G * mass planet * mass sattelite / r^2 = mass sat. * v^2 /r

Then I have v = sqrt( G * mass planet/ r).

So the velocity is not directly proportional to the square root of r, but inversely proportional! Right?

 

[haruspex]

If I have G * mass planet * mass sattelite / r^2 = mass sat. * v^2 /r

Then I have v = sqrt( G * mass planet/ r).

So the velocity is not directly proportional to the square root of r, but inversely proportional! Right?

Yes.

 

[drvrm]

If I have G * mass planet * mass sattelite / r^2 = mass sat. * v^2 /r

Then I have v = sqrt( G * mass planet/ r).

So the velocity is not directly proportional to the square root of r, but inversely proportional! Right?

your angular momentum is equal to m.v. r and if you say v to be proportional to 1/sqrt(r) ,

then you get the ang. momentum as directly proportional to sqrt(r) ;
i think that is what you need .
regarding dependence on mass - if you replace v in terms of mass and r which are under sqrt sign ---one can say that angular momentum is proportional to sqrt(mass) also

II. directly proportional to the square root of R
III. directly proportional to the square root of M.

The correct answer apparently is II and III.

-

so at least it corroborates the answer

 

[RoboNerd]

then you get the ang. momentum as directly proportional to sqrt(r) ;

No, I think it would be inversely proportional?

 

[drvrm]

No, I think it would be inversely proportional?

so , again i repeat for your consideration:
L = m.v.r ,
v = constant / sqrt(r) ; substitute in L (ang. momentum)
L= m. constant / sqrt(r) . r = m . constant. sqrt(r) so L is proportional to sqrt(r)
as r = sqrt(r). sqrt(r)