Range of a cannon using trigonometry?

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SUMMARY

The discussion focuses on solving a trigonometric equation related to the range of a cannon. The equation presented is 0 = x[(tanα - tanθ) - (gx / 2Vo²Cos²(α))], which simplifies to x = (tanα - tanθ) / g * (2Vo²Cos²(α)). The user initially struggled with rearranging the equation but ultimately resolved the issue independently, highlighting the simplicity of the solution once understood.

PREREQUISITES
  • Understanding of trigonometric functions, specifically tangent.
  • Familiarity with projectile motion equations.
  • Knowledge of algebraic manipulation techniques.
  • Basic physics concepts related to gravity (g) and initial velocity (Vo).
NEXT STEPS
  • Study the derivation of projectile motion equations in physics.
  • Explore the application of trigonometric identities in solving physics problems.
  • Learn about the effects of angle and initial velocity on projectile range.
  • Practice algebraic rearrangement techniques for complex equations.
USEFUL FOR

Students studying physics, particularly those focusing on projectile motion, as well as educators looking for examples of trigonometric applications in real-world scenarios.

Futurestar33
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Homework Statement


I am just stuck on a step in my problem , I have found the solution but have been attempting rearrange the equation but I just don't get it. Its probably a simple step

Homework Equations



0=x[(tanα-tanθ)-(gx/2Vo^2Cos^2(α)]

then this forms into this

x=(tanα-tanθ/g)(2Vo^2Cos^2(α))

The Attempt at a Solution


How do you get the X to the other side. There is a parentheses next to the x so you can divide anything out?
 
Last edited:
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Nevermind I figured it out. Easy lol
 

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