The discussion centers on determining the range of values for the constant a in the quadratic inequality ax² + 2ax + 3 ≥ 0 when a > 0. The discriminant, calculated as D = b² - 4ac, is derived to be D = 4a² - 12a. The solution indicates that the range of a must satisfy 0 < a ≤ 3 for the inequality to hold true for all real numbers.
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No, the discriminant is 4a2 - 12a. What do your two values have to do with the discriminant? (I know, but I am trying to get you to be accurate in what you say.)ybhathena said:Homework Statement
Determine the range of values of the constant a so that the solution of ax^2+2ax+3>=0 (when a >0) is all real numbers
Homework Equations
D = b^2-4ac
The Attempt at a Solution
The discriminant is 0, 3.
ybhathena said:I need to know how to arrange them to get the range. The range is 0<a<=3 in the answers. How do I get it?