Rank Designs A-F: Largest to Smallest Tension

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SUMMARY

The discussion centers on ranking six design scenarios (A-F) based on the tension in a supporting cable for a sign hung from a pole. The scenarios vary based on the cable's attachment point, affecting the tension required. The correct ranking, as confirmed by forum participants, is C=F>D>A>B>E. The tension calculations utilize the formula tau = rFsin(theta), where r is the distance from the hinge and theta is the angle of the force relative to the pole.

PREREQUISITES
  • Understanding of torque and its calculation using tau = rFsin(theta)
  • Knowledge of trigonometry, particularly angles and sine functions
  • Familiarity with tension forces in physics
  • Basic principles of static equilibrium in mechanics
NEXT STEPS
  • Study the principles of static equilibrium in mechanical systems
  • Learn about torque calculations in different scenarios
  • Review trigonometric functions and their applications in physics
  • Explore real-world applications of tension in structural engineering
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This discussion is beneficial for physics students, engineering students, and professionals involved in structural design and mechanics, particularly those focusing on tension and torque calculations.

wanamaa
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Homework Statement


A sign is to be hung from the end of a thin pole, and the pole supported by a single cable. Your design firm brainstorms the six scenarios shown below. In scenarios A, B, and D, the cable is attached halfway between the midpoint and end of the pole. In C, the cable is attached to the mid-point of the pole. In E and F, the cable is attached to the end of the pole.

Rank the design scenarios (A through F) on the basis of the tension in the supporting cable.
Rank from largest to smallest. To rank items as equivalent, overlap them.
200911261637506339485027042025004529.jpg

Homework Equations



tau = rFsin(theta) ,where r is the distance from the hinge to the force and theta is the angle of the force relative to the pole.

The Attempt at a Solution


Well, the tension of design E is equal to the weight of the sign, since it is in the same location. C and F are equal in torque because rFsin(30) = 1/2 r. Both A and B have the cable attached at the same point and, since A is at an angle less than 90 degrees, A requires more tension than B. On that same note, A has a greater angle than D, so A requires less tension.

I've only got one shot at this and I would like it figured out by Friday. My educated guess is that C = F > A > D > B > E, but I want to make sure before I submit my answer. I'm horrible with problems with only variables. Could someone verify if I'm right/close/wrong? Any help would be awesome.
 
Last edited:
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wanamaa: You are currently close. Also, it appears you have the wrong formula for cable tension T. Review your trigonometry.
 
the ranking order is: C=F>D>A>B>E
 

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