- #1

hendrix7

- 36

- 8

## Homework Statement

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A simple suspension bridge consists of a uniform plane horizontal rectangular roadway of mass M, freely supported by two sets of four equally spaced light vertical cables. Each set of four cables lies in the same vertical plane and is attached to one edge of the roadway. These cables are in turn attached to a single light cable ABCDEF as shown below. A, B, C are on the same horizontal level as F, E, D respectively.

A and F are 8 m and C and D are 2 m above the level of the roadway which has length 20 m. AF = 20 m. Given that the tensions in all vertical cables are the same, show that the tension in CD is Mg/4 and find the tensions in each of the parts AB, BC, DE, EF of the connecting cable.

## Homework Equations

## The Attempt at a Solution

resolving vertically: Mg = 4T (T = tension in all vertical cables).

Actually, I'm not sure of this. What about the reactions at A and F?

Let tension in BC = T

_{1}

Let a = acute angle BC makes with CD

tension in CD = T

_{1}cos a

now I'm stuck. How do I find cos of a?

any help greatly appreciated,

Jimi