Rank Resistances: A, B, C, A+B, B+C, A+B+C

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SUMMARY

The discussion focuses on ranking the resistances of three conductors (A, B, and C) based on their configurations and dimensions. The resistances are calculated using the formula R = ρ (L/A), where ρ is the resistivity, L is the length, and A is the cross-sectional area. The conductors are arranged such that B fits inside A, and C fits inside B. The final ranking of resistances from greatest to least is A + B + C, A + B, B + C, and the individual conductors A, B, and C.

PREREQUISITES
  • Understanding of electrical resistance and the formula R = ρ (L/A)
  • Knowledge of resistivity and its role in conductor performance
  • Familiarity with geometric calculations for cross-sectional areas
  • Basic principles of series and parallel resistances
NEXT STEPS
  • Research the impact of resistivity on conductor performance in different materials
  • Learn about the effects of conductor geometry on resistance
  • Study series and parallel resistor combinations in electrical circuits
  • Explore practical applications of resistance calculations in electrical engineering
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Students studying electrical engineering, physics enthusiasts, and professionals involved in circuit design and analysis will benefit from this discussion.

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Homework Statement


The figure below shows cross sections through three long square conductors of the same length and material, with square cross sections of edge lengths as shown. Conductor B fits snugly within conductor A, and conductor C fits snugly within conductor B.

Rank the following according to their end-to-end resistances, greatest first: the individual conductors and the combinations of A + B (B inside A), B + C (C inside B), and A + B + C (B inside A inside C).

http://img14.imageshack.us/img14/7955/phys2.jpg

Homework Equations



R = p (L/A)

The Attempt at a Solution


Each of them have a different length and area, so I don't know how to go about this problem.
 
Last edited by a moderator:
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You have a relevant equation and the dimensions of your conductors. That's all you need.
 

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