Rate of Gravitational Force (Power)

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Homework Help Overview

The discussion centers around the calculation of the rate at which gravitational force does work on a projectile, specifically a 2.0 kg object moving at 4.0 m/s at an angle of 30 degrees above the horizontal. Participants are exploring the relationship between gravitational force, work, and power in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand why the angle used in calculations is 120 degrees instead of 60 degrees, questioning the relationship between the angle of the velocity vector and the gravitational force vector. There are discussions about the implications of using different angles in the context of work done.

Discussion Status

Some participants have offered insights into the definitions of work and the geometric interpretation of the vectors involved. There is an acknowledgment of the relationship between cos(60) and cos(120), and a participant expresses a clearer understanding of the angle's significance. However, there remains a request for visual aids to assist in correctly drawing the vectors for future reference.

Contextual Notes

Participants are navigating the complexities of vector angles in relation to gravitational force and work, emphasizing the importance of accurate diagramming for problem-solving in exams. There is a recognition of the need for clarity in visual representation to avoid confusion in future calculations.

Lori

Homework Statement


At what rate is the gravitational force doing work on a 2.0 kg projectile at an instant when the velocity of the projectile is 4.0 m/s directed 30 degrees above the horizontal.

the answer is -39 W but i need help on why!

Homework Equations


P = W/T
Power = Work*V
=Force*cos(theta)*V

The Attempt at a Solution


I know that the force of the gravity is just 9.8*2, but why is the angle that i plug in cos(120) ? I'm not sure why/how we use angle of 120 as oppose to 90-30 = 60 degrees...

If you can provide a sketch for me visually, it would help a lot...

Here's what i thought:
upload_2017-11-7_19-40-49.png
 

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How does cos(60) compare to cos(120)? This might help answer your question.
 
phyzguy said:
How does cos(60) compare to cos(120)? This might help answer your question.
Ohh, it's just the negative of it... but i get why work would be negative in this case, but how can i draw it so that i don't mess up the angles next time? Since i have to do it right on the exam, i just draw the diagram and don't think of the signs! Is there a actual sketch of it that it should look like, so that i can learn how to draw it?
 
Look at the definition of work done. Eg.. W=f.s

The angle between the velocity and force of gravity vectors is 120 degrees when they are drawn from the same point.
 
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CWatters said:
Look at the definition of work done. Eg.. W=f.s

The angle between the velocity and force of gravity vectors is 120 degrees when they are drawn from the same point.
Ohhhh. I see it now. Thanks
20171107_201215.jpg
 

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This is the way I would draw it...

Vectors.jpg
 

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