Ratio and proportion - HEEEEELLLLPP

  • Thread starter Thread starter lazykidarr
  • Start date Start date
  • Tags Tags
    Ratio
Click For Summary
SUMMARY

The discussion focuses on solving a ratio and proportion problem involving the monthly incomes of three individuals: A, B, and C. The incomes are given in ratios: A to B is 8:7 and B to C is 5:3. Given that C's income is Rs. 3,360, the solution shows that A's income can be calculated as Rs. 6,400 using the derived equations A = (40/21)C. The problem emphasizes basic arithmetic rather than advanced mathematical concepts.

PREREQUISITES
  • Understanding of ratios and proportions
  • Basic arithmetic operations (addition, multiplication, division)
  • Ability to manipulate algebraic equations
  • Familiarity with solving word problems in mathematics
NEXT STEPS
  • Practice solving ratio and proportion problems
  • Learn how to set up equations from word problems
  • Explore basic algebraic manipulation techniques
  • Review arithmetic operations and their applications in problem-solving
USEFUL FOR

Students preparing for entrance exams, individuals seeking to improve their mathematical problem-solving skills, and anyone looking to understand ratios and proportions in practical scenarios.

lazykidarr
Messages
1
Reaction score
0
Hi!
I don't have ANY IDEA on how to do ANY kind of math problem coz i am not a math student but i have to do some QA questions for my entrance exams so I need a little bit of help here!
so...here's the question:-

The monthly incomes of A and B are in the ratio 8:7 and those of B and C are in the ratio 5:3. If the monthly income of C is Rs.3,360, find the monthly income of A.

Options:
a) Rs.3500
b) Rs.4200
c) Rs.5600
d) Rs.6400
I tried solving the problem and I can't get the answer in more than 3 digits! Desperately need help here!
 
Physics news on Phys.org
A ratio is a fraction and proportion is a statement that two fractions are equal. Here you are told that A/B= 8/7 and that B/C= 5/3. From the first equation, multiplying both sides by 7B, 7A= 8B. Dividing both sides by 8, B= (7/8)A. Doing the same with the second equation, 3B= 5C, B= (5/3)C. So B= (7/8)A= (5/3)C. Multiply both sides by 8/7 to get A= (8/7)(5/3)C= (40/21)C. Since C= 3,360, A= (40/21)(3360). I don't understand what you mean by "more than 3 digits". It just simple arithmetic. Are you allowed to use a calculator? Even without a calculator it is easy to see that 3360 is divisible by 3: 3360/3= 1120 so 3360/21= 1120/7 and, remarkably, 1120/7= 160. Can you multiply 40(160)?

And this surely does not belong in "Calculus and Beyond". It is, as I said, simply arithmetic.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K