Rational and Irrational Numbers

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SUMMARY

The discussion focuses on proving that the sum of a rational number and an irrational number is irrational using proof by contradiction. The proof begins with the assumption that a rational number \( a = \frac{p}{q} \) (where \( p \) and \( q \) are coprime integers) and an irrational number \( b \) can sum to a rational number \( \frac{s}{t} \). The conclusion is reached by demonstrating that this leads to a contradiction, as \( b \) can be expressed as a ratio of integers, contradicting its irrationality. Additionally, the discussion touches on the misconception that the sum of two irrational numbers is always irrational, providing a counterexample with \( \sqrt{2} \) and \( 5 - \sqrt{2} \).

PREREQUISITES
  • Understanding of rational and irrational numbers
  • Familiarity with proof by contradiction
  • Basic knowledge of coprime integers
  • Ability to manipulate algebraic expressions involving fractions
NEXT STEPS
  • Study the properties of rational and irrational numbers in depth
  • Learn more about proof techniques in mathematics, particularly proof by contradiction
  • Explore counterexamples in number theory to understand exceptions
  • Investigate the implications of irrational numbers in algebraic expressions
USEFUL FOR

Students of mathematics, particularly those studying precalculus or number theory, as well as educators looking for examples of proofs involving rational and irrational numbers.

lokisapocalypse
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I need to show that a rational + irrational number is irrational. I am trying to do a proof by contradiction.

So far I have:

Suppose a rational, b irrational.
Then a = p/q for p, q in Z.
Then a + b = p/q + b = (p + qb) / q
But I don't know where to go from here because I still have a rational plus an irrational and that is what I am trying to show.

Also, would a similar proof work to show that an irrational + irrational = irrational?
 
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lokisapocalypse said:
I need to show that a rational + irrational number is irrational. I am trying to do a proof by contradiction.

So far I have:

Suppose a rational, b irrational.
Then a = p/q for p, q in Z.
Then a + b = p/q + b = (p + qb) / q
But I don't know where to go from here because I still have a rational plus an irrational and that is what I am trying to show.

When you're doing a contradiction, you should assume the opposite of the premise and show that it leads to an absurd conclusion.

For this problem, try this :

Let a = \frac{p}{q} where p and q are coprime integers.

b is irrational.

Now let us say their sum is a rational number, which can be expressed as \frac{s}{t}[/tex], where s and t are coprime integers.<br /> <br /> Then,<br /> <br /> a + b = \frac{s}{t}<br /> <br /> b = \frac{s}{t} - a = \frac{s}{t} - \frac{p}{q} = \frac{sq - pt}{qt}<br /> <br /> We have just shown that b can be expressed as the ratio of two integers. But b is irrational.<br /> <br /> This is a contradiction. Hence the assumption is false and the original premise is true.<br /> <br /> <blockquote data-attributes="" data-quote="" data-source="" class="bbCodeBlock bbCodeBlock--expandable bbCodeBlock--quote js-expandWatch"> <div class="bbCodeBlock-content"> <div class="bbCodeBlock-expandContent js-expandContent "> Also, would a similar proof work to show that an irrational + irrational = irrational? </div> </div> </blockquote><br /> This isn&#039;t even true in general. What can you say about the sum of \sqrt{2} and (5 - \sqrt{2}) ?
 
I need to show that a rational + irrational number is irrational. I am trying to do a proof by contradiction.

The proof is one line. :smile:

So, you're doing proof by contradiction, and have assumed that there are rational numbers p and q, and an irrational number z, such that:

p + z = q

right?


Also, would a similar proof work to show that an irrational + irrational = irrational?

It is also fairly easy to construct counterexamples... but the method might be easier to find once you've done the first problem.
 
I need to show that a rational - irrational number is irrational. I am trying to do a proof by contradiction.
Plz send me the related answer as I need it...
 
Last edited:
Since this clearly has nothing to do with physics, I am moving it to "precalculus homework".
 
Anjuyogi, take a look at the previous posts?
 

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