Rational roots - standard form of equation

  • Thread starter Janinever
  • Start date
13
0
Hi everybody!

I've hit a blank with regards to this 1 equation on a old exam paper - think I've overloaded myself a bit and just feel a bit like a airhead at the moment!

I understand the actual method and getting to the answer but it starts off with a equation which you then need to get to a standard form to use the formula to check if the roots are rational.

The initial equation is this :

4x^2 + 2kx - k = 2x

Then on the memorandum this is taken to standard form so the info can be substituted into the formula Δ = b^2 - 4ac

the standard form they then write that initial equation in is :

4x^2 + 2(k-1)x-k = 0

How do they get from 4x^2 + 2kx - k = 2x to this 4x^2 + 2(k-1)x-k = 0

The rest I understand entirely. Literally just the above has be scratching my head!

Please help :)

Thank you!
 

pwsnafu

Science Advisor
1,080
85
How do they get from 4x^2 + 2kx - k = 2x to this 4x^2 + 2(k-1)x-k = 0
Sometimes you overlook the obvious answers. Just subtract 2x from both sides.
 
13
0
Thank you!
 

Related Threads for: Rational roots - standard form of equation

Replies
8
Views
6K
  • Posted
Replies
2
Views
2K
  • Posted
Replies
5
Views
2K
  • Posted
Replies
6
Views
17K
Replies
6
Views
6K
Replies
6
Views
1K
Replies
7
Views
3K
Replies
6
Views
3K

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving

Hot Threads

Top