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## Homework Statement

When 10.7 g of an unknown, non-volatile, non-electrolyte, X was dissolved in 100. g of water, the vapor pressure of the solvent decreased from 23.8 torr to 23.6 torr at 298 K. Calculate the molar mass of the solute, X.

## Homework Equations

The answer is 227, but I know I'm doing wrong in the equation somewhere.

## The Attempt at a Solution

100gH20 = 5.56 moles, Molar Fraction = .991

.991 = 5.56 / 5.56 + x =

5.51 + .991x = 5.56

.05 / .991 = 05 <---subtracted

10.7 / .05 = 214 g

Would appreciate any help!