What is the molar mass of the unknown?

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Discussion Overview

The discussion revolves around calculating the molar mass of an unknown substance based on its freezing point depression when dissolved in lauric acid. Participants explore the application of the freezing point depression equation and address the accuracy of calculations and significant figures.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • The initial calculation of molar mass was presented, yielding a result of 540 g/mol.
  • Some participants suggest improvements, such as avoiding rounding down intermediate results, which could affect the final molar mass by approximately 8 g.
  • There is a recommendation to include units in calculations for clarity.
  • A later reply indicates that the revised answer of 538.46 g/mol is overly precise given the available data, suggesting that fewer significant digits should be used.
  • Participants note that rounding errors influenced the transition from 538 to 530 g/mol in the calculations.

Areas of Agreement / Disagreement

Participants generally agree on the need for accuracy in calculations and the importance of significant figures, but there is no consensus on the final value of the molar mass due to differing opinions on the precision of the calculations.

Contextual Notes

Limitations include the potential for rounding errors and the dependence on the accuracy of the freezing point depression constant (Kf) used in the calculations.

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Homework Statement



A 1.40 g sample of an unknown is dissolved in 8.10 g of lauric acid. The freezing point is depressed 1.23 oC. What is the molar mass of the unknown?



Homework Equations



Delta T = Kf * m



The Attempt at a Solution



Delta T = Kf * m
=> m = 1.23 / 3.9 = 0.32

mole solute = 0.32 * 0.0081 = 0.0026 moles.

=> Molar mass = 1.40 / 0.0026 = 540 g/mol = final answer.

Am I doing correct? Please let me know!
 
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Not bad. Two thngs that will make your solution better.

1. Don't round down intermediate results (check that it changes molar mass by about 8g).
2. Don't ignore units in your calculations, they are much easier to follow when it is obvious what is what of what.
 
Last edited by a moderator:
Borek said:
Not bad. Two thngs that will make your solution better.

1. Don't round down intermediate results (check that it changes molar mass by about 8g).
2. Don't ignore units in your calculations, they are much easier to follow when it is obvious what is what of what.

--
chemical calculators - buffer calculator, concentration calculator
www.titrations.info - all about titration methods


Thanks so much for your response!

I have edited my answer to:

Delta T = Kf * m => m = 1.23 / 3.9 = 0.32 m

mole solute = 0.32 * 0.0081 = 0.0026 mole

Molar mass of the unknown = 1.40 / 0.0026 = 538.46 g/mol .

Hope it better ;)
 
This time you overdid - you don't have enough information to give 5 significant digits in the answer :smile: But you see that rounding errors were responsible for 538 being 530.
 
Last edited by a moderator:

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