- #1
wmiddlebrook
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I am doing a Mastering Physics problem that I am stumped on. The question is:
"If this resolving power is diffraction-limited, to what effective diameter of your eye's optical system does this correspond? Use Rayleigh's criterion and assume that the wavelength of the light is 550 nm ."
The resolving power of the eye is 1.67×10−2 degrees.
I know that sin(angle)=1.22*(wavelength/diameter) and I keep getting .0023 mm as the answer and getting it wrong.
WITHOUT giving the answer, how do you approach this problem/ what am I doing wrong?
I am thinking that I need to multiply my number by the diameter of the eye to get the length in the eye, but I am not sure.
"If this resolving power is diffraction-limited, to what effective diameter of your eye's optical system does this correspond? Use Rayleigh's criterion and assume that the wavelength of the light is 550 nm ."
The resolving power of the eye is 1.67×10−2 degrees.
I know that sin(angle)=1.22*(wavelength/diameter) and I keep getting .0023 mm as the answer and getting it wrong.
WITHOUT giving the answer, how do you approach this problem/ what am I doing wrong?
I am thinking that I need to multiply my number by the diameter of the eye to get the length in the eye, but I am not sure.