Reaction between barium and sulphate?

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SUMMARY

The experiment demonstrated that barium reacts with sulfate to form a precipitate only in acidic conditions, specifically when barium nitrate and copper sulfate solutions were used. The presence of HNO3 facilitated the oxidation of barium, producing soluble Ba2+ ions that reacted with sulfate ions. In contrast, under alkaline conditions with NaOH, barium remained undissolved due to the lack of electron-stripping reactions, preventing the formation of Ba2+. The results indicate that the pH level significantly influences the precipitation of barium sulfate.

PREREQUISITES
  • Understanding of precipitation reactions
  • Knowledge of acid-base chemistry
  • Familiarity with barium nitrate and copper sulfate solutions
  • Basic concepts of solubility and ionization
NEXT STEPS
  • Research the solubility product constant (Ksp) of barium sulfate
  • Learn about the effects of pH on precipitation reactions
  • Investigate the role of complexation in alkaline solutions
  • Explore the principles of ionic charge and particle coalescence in precipitate formation
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Chemistry students, laboratory technicians, and educators interested in precipitation reactions and the effects of pH on solubility.

ASidd
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We did an experiment in class today with Barium and sulfate.
To one of the experiments we added a couple of drops of HNO3 to make it acidic and to the other one NaOH to make it alkaline.
the barium and then sulfate
The only one where they both reacted to make a precipitate were the acidic solutions

So I want to know that is this a known fact that Barium will only react with Sulfate under acidic conditions? Why?
 
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When you have a metal in the presence of an acid, you'll see that a gas is produced. This is hydrogen gas from the H+ reacting with the metal, stripping it of electrons, forming H2, and producing soluble oxidized metal ions.

Oxidizing barium metal results in soluble Ba2+, which then reacts with the sulfate. Under basic or neutral conditions, there is nothing to strip electrons from the barium so it will remain undissolved and no Ba2+ will be present in solution.
 
yes but we had barium in the form of barium nitrate solution and copper as copper sulphate solution.Wouldn't both already be present as ions in solutions?
 
aroc91 said:
Under basic or neutral conditions, there is nothing to strip electrons from the barium so it will remain undissolved and no Ba2+ will be present in solution.

Barium is so reactive it will react with water on its own.

I can't think of any reason why barium sulfate would not precipitate in alkaline solutions.
 
yes but we proved that it doesn't.
Is there a reason for the reaction occurring at a low PH
 
What salts were used in the experiment? Do you know concentrations of reagents used?

In high pH barium can be slightly complexed by OH- anions, but the stability constant is so low (around 0.6) it should not change anything. Ba(OH)2 itself is weakly soluble (Ksp values - 3.6 for hydroxide and 10 for sulfate) but you say you have not observed any precipitate at all, so it doesn't matter as well.

Strange result.
 
We used barium nitrate solution and copper sulphate solution. About 10drop each. Then 5 drops of the acid or alkali.

It was a simple precipitation reaction.
 
The concentration would be about 0.1 mol
 
Oh, duh. I was thinking it was a transition metal for some reason. Disregard me.
 
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And you have not seen a copper hydroxide precipitation in the alkaline solution?
 
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Maybe it has to do with the electrical charge of the solid BaSO4 particles initially formed. I know that in some cases, particles that will form a precipitate, have initially an electrical charge which depends on which one between cation or anion is more absorbed by the particles. Maybe, but I'm just speculating, BaSO4 particles absorb SO42- in eccess, becoming negatively charged, so adding H+ could reduce this charge and favour their coalescing into a solid precipitate, while OH- ions could prevent this coalescence.
 

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