Reactivity of solutions with the same anion

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Discussion Overview

The discussion centers on the reactivity of anions in two different aqueous solutions containing the same anion but differing in their cation and solubility characteristics. Participants explore whether the reactivity of the anion is influenced by the cations present or the solubility of the compounds involved.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant questions whether the anion's reactivity would be the same in both solutions, suggesting that it might depend on the cations or the solubility of the compounds.
  • Another participant proposes that the reactivity could differ due to varying bond strengths in the compounds, indicating that the presence of different cations could affect the anion's reactivity even when solvated.
  • A participant introduces the concept of ionic strength and activity coefficients, referencing Debye-Hückel theory as potentially relevant to the discussion.
  • It is noted that CaF2 is practically insoluble in water, which may impact the concentration of F- in solution.
  • A participant mentions that the saturated concentration of CaF2 is approximately 4x10-4 M in F-, suggesting that this concentration is reasonable for preparation.

Areas of Agreement / Disagreement

Participants express differing views on the reactivity of the anion in the two solutions, with no consensus reached on whether the reactivity is the same or influenced by other factors.

Contextual Notes

Participants have not fully explored the implications of ionic strength and activity coefficients, and the discussion includes assumptions about solubility and the effects of different cations that remain unresolved.

aekotra
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If I have two aqueous solutions of two different compounds (with different solubility) that result in equal amounts of the same anion, should the anion in those solutions have the same reactivity or not?

An example:
Solution A
CaF2 (aq)

Solution B
NaF (aq)

The solutions are prepared such that both contain the same amount of F-. Is F- more or less reactive in either of the solutions? Would it be dependent on the cations or solubility of the compound?
 
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Before we will start to discuss details - what is your opinion? Per forum rules you should try to answer the question by yourself first.
 
I'm leaning towards the idea that the reactivity would be different, perhaps due to the differing bond strengths in the compounds. Different cations in proximity to the anion would affect the anion's reactivity in ways particular to those species, despite both having been solvated.
 
Last edited:
Have you heard about ionic strength of the solution and activity coefficients? Debye-Hückel theory?
 
CaF2 is practically insoluble in water.
 
Saturated CaF2 is something like 4x10-4 M in F-. Not much, but quite a reasonable concentration, easy to prepare.
 

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