Real roots of complex polynomials

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SUMMARY

The discussion focuses on proving that a polynomial f of degree n with all roots real and of multiplicity 1 has at most one more real root than its derivative f'. It references the Gauss-Lucas theorem, which states that every root of f' lies within the convex hull of the roots of f. Additionally, it is established that if zk is a root of f, then f'(zk) is non-zero, confirming zk is not a root of f'. The conversation highlights the relationship between the real and non-real roots of f and f' in this context.

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Homework Statement



Let f be a polynomial of degree n >= 1 with all roots of multiplicity 1 and real on R. Prove that
f has at most one more real root than f'
f' has no more nonreal roots than f

Homework Equations



We are given the Gauss Lucas theorem: Every root of f' is contained in the convex hull of the roots of f.
Also previously proved is that if zk is a root of multiplicity 1 of f(z) then f'(zk) !=0 (zk is not a root of the derivative of f)

we express f(z)=c(z-z1)...(z-z2) where for each k f(zk)=0.

The Attempt at a Solution



I'm lost at where to begin, I've tried looking at it different ways but am not seeing where the difference of real and non real roots comes in.
Any suggestions? (if you can help I'd prefer hints rather than the whole answer)

Thanks
 
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