Rearranging a Relativity Equation

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SUMMARY

The discussion focuses on rearranging the relativistic Doppler effect equation, specifically f = √((c + u)/(c - u))f₀, to solve for the relative velocity u between an electromagnetic source and an observer. The participants successfully derive the formula u = (c((f/f₀)² - 1))/((f/f₀)² + 1) and confirm its correctness. They also address a specific scenario where a 3.0% decrease in frequency is analyzed, clarifying that f₀ should be set to 1 and f to 0.97 to find the appropriate relative velocity.

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[SOLVED] Rearranging a Relativity Equation

Homework Statement



Rewrite equation:

f = \sqrt{\frac{c + u}{c - u}}f_0

to find the relative velocity u between the electromagnetic source and an observer in terms of the ratio of the observed frequency and the source frequency of light.

What relative velocity will produce a 3.0 decrease in frequency and

Homework Equations



Rearangement of:

f = \sqrt{\frac{c + u}{c - u}}f_0

The Attempt at a Solution



I seem to get stuck when trying to rearrange the equation:

f = \sqrt{\frac{c + u}{c - u}}f_0

\frac{f}{f_0} = \sqrt{\frac{c + u}{c - u}}

(\frac{f}{f_0})^2 = \frac{c + u}{c - u}

(c - u)(\frac{f}{f_0})^2 = c + u

But I am not sure where to go from here.

Any suggestions?

TFM
 
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TFM said:
(c - u)(\frac{f}{f_0})^2 = c + u
You're doing fine; don't stop now.

c(\frac{f}{f_0})^2 - u(\frac{f}{f_0})^2 = c + u

Next: Move all the terms containing u to one side.
 
Would that give:

c(\frac{f}{f_0})^2 - c = u(\frac{f}{f_0})^2 + u

TFM
 
Do uou now factor out the u:

c(\frac{f}{f_0})^2 = u ((\frac{f}{f_0})^2 + 1)

Tnhe divide over to get:

u = \frac{c(\frac{f}{f_0})^2 - c}{(\frac{f}{f_0})^2 + 1}

Does this look right?

TFM
 
Looks good! (I would factor out the c to make it more readable.)
 
That would give:

u = \frac c((\frac{f}{f_0})^2) - 1}{(\frac{f}{f_0})^2 + 1}


What relative velocity u will produce a 3.0 % decrease in frequency

For the actual question, do I put f_0 as 1 and f as 0.97?

TFM
 
TFM said:
That would give:

u = \frac c((\frac{f}{f_0})^2) - 1}{(\frac{f}{f_0})^2 + 1}
:confused: Redo this. (Probably a formatting error.)
 
That definitely isn't right :

u = \frac{c((\frac{f}{f_0})^2 - 1)}{(\frac{f}{f_0})^2 + 1}

TFM
 
Looks good.
 
  • #10
The actual question itself is:

What relative velocity u will produce a 3.0 % decrease in frequency

For this, should I put f_0 as 1 and f as 0.97?

TFM
 
  • #11
TFM said:
For this, should I put f_0 as 1 and f as 0.97?
Makes sense to me.
 
  • #12
It gives, the right answer, Thanks

One last thing, what is the question actually asking to find:

What relative velocity u will produce an increase by a factor of 3 of the observed light?

Does it want the freuqncy to be incresed by three factors?

TFM
 
  • #13
I'm no more a mind reader than you are! :smile: But since the problem seems to be talking about frequency and Doppler shifts, I would assume they mean that the observed frequency is three times the original.
 
  • #14
I calculated it to be 0.8, which is the answer, so I should say it is, as well.

Thats the second poorly worded question I've had this week:rolleyes:

Thanks for all the help,

TFM
 

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