Rearranging Equations: 3x^2 + 2y^2 = 35

[Stratosphere]

Homework Statement

3x$$^{2}$$ + 2y$$^{2}$$ = 35

Homework Equations

The Attempt at a Solution

I rearrangged it for x$$^{2}$$ and got $$-\frac{2}{3}y+11\frac{2}{3}=x^{2}$$
Is this right?

 

[rock.freak667]

It looks correct to me

 

[cshum00]

I don't think it is 11(2/3)

$3x^2 + 2y^2=35$
$3x^2 = 35 - 2y^2$
$x^2 = 35/3 - (2/3)y^2$

but $35/3 = 11(2/3)$?
$11.66.. \neq 7.33..$

 

[rock.freak667]

I don't think it is 11(2/3)

$3x^2 + 2y^2=35$
$3x^2 = 35 - 2y^2$
$x^2 = 35/3 - (2/3)y^2$

but $35/3 = 11(2/3)$?
$11.66.. \neq 7.33..$

I believe $11\frac{2}{3}$ meant 11 and 2/3 not 11 multiplied by 2/3

 

[HallsofIvy]

But it should be
$$x^2= -\frac{2}{3}y^2- 11\frac{2}{3}$$
Not
$$x^2= -\frac{2}{3}y- 11 \frac{2}{3}$$

I presume the missing exponent on y was a typo.

 

[cshum00]

I believe $11\frac{2}{3}$ meant 11 and 2/3 not 11 multiplied by 2/3

lol. Mixed numbers. It has been so long since i last used them and it should be best to be avoided.