Rearranging Formula to Find 't'

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SUMMARY

The discussion focuses on rearranging the formula s = ut + 1/2at² to isolate the variable 't'. Participants emphasize the importance of understanding quadratic equations and the quadratic formula, which is expressed as t = (-b ± √(b² - 4ac)) / (2a). The conversation highlights the necessity of showing work for clarity and understanding, as well as the method of completing the square as an alternative approach to solving for 't'.

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  • Understanding of basic algebraic manipulation
  • Familiarity with quadratic equations
  • Knowledge of the quadratic formula
  • Concept of completing the square
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  • Study the quadratic formula in detail, including its derivation and applications
  • Learn the method of completing the square for solving quadratic equations
  • Practice rearranging formulas in physics, particularly kinematic equations
  • Explore real-world applications of quadratic equations in physics and engineering
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Students studying physics or mathematics, educators teaching algebra and kinematics, and anyone looking to improve their problem-solving skills in quadratic equations.

spritchs
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1. Please can you help me rearrange this formula to find t. I am finding it very difficult.



2. Rearrange formula s=ut+1/2at^2 to find 't'
 
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You must show your work in order to get our help on the PF. What can you tell us about the quadratic equation and how it is used to solve for t in equations like the one you show?
 
um I know that since both side of the equation are equal anything you do to oneside you must do to the other so it stays equal while rearranging and for everything that has already been done to the first part you must do the opposite.
 
Last edited:
This is a quadratic equation. The easiest way to solve such an equation is to use the quadratic formula. Do you know it?
 
I don't sorry but after looking on the internet I think its:
ax^2+bx+c=0
 
No, that's the general form of a quadratic equation. The quadratic formula says that x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
 
spritchs said:
um I know that since both side of the equation are equal anything you do to oneside you must do to the other so it stays equal while rearranging and for everything that has already been done to the first part you must do the opposite.

You can solve it using what you've stated here too. Did you learn about "completing the square"?

hint: if not, do a google search on it
 

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