- #1
paprika213
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https://i.imgur.com/4nynNBg.png
I cannot understand for the life of me why this problem doesn't just use T = 2πr/v to solve for the period to get T = 2π(Lsinβ)/v. Instead, it rearranges the formula for a(rad) = (4π^2R)/T^2 to solve for T, and arrives at a totally different answer, T = 2π√(Lcosβ/g).
So why doesn't the formula T = 2πr/v apply in this case?
I cannot understand for the life of me why this problem doesn't just use T = 2πr/v to solve for the period to get T = 2π(Lsinβ)/v. Instead, it rearranges the formula for a(rad) = (4π^2R)/T^2 to solve for T, and arrives at a totally different answer, T = 2π√(Lcosβ/g).
So why doesn't the formula T = 2πr/v apply in this case?
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