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Simon Bridge

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You just said the reason: they retreat faster than the speed of light.

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However why would that fact mean a photon emitted from that galaxy would never reach Earth?You just said the reason: they retreat faster than the speed of light.

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However why would that fact mean a photon emitted from that galaxy would never reach Earth?

As the photon moves towards Earth at ##c##, the distance between Earth and the photon is increasing at greater than ##c##, so (as long as space keeps expanding at its current rate or faster) the photon will simply get further and further away.

If the expansion of space was suddenly or gradually to stop, then that would be a different matter!

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Regards Andrew

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Simon Bridge

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http://physics.stackexchange.com/qu...ceding-faster-than-light-visible-to-observers

... so amend the above observation: the galaxies are receeding from faster than the speed of light and not all the photons are able to reach a slower expansion part of the Universe. But you get the idea that farther away a galaxy the harder it is for it's light to reach us... at some point it won't be able to. The recession speed being equal to the speed of light is just not the cutoff point.

https://en.wikipedia.org/wiki/Event_horizon#Cosmic_event_horizon

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Regards Andrew

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George Jones

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There is a fading (and not just at and beyond the Hubble radius). The expansion of the universe has, in two ways, diminished the energy flux that we receive beyond just a distance effect. The energy of light is inversely proportional to its wavelength (energy of a photon is ##E=hc/\lambda)##. As the light travels to us, the expansion of the universe expands the wavelength of the light by a factor of 1+z, where z is redshift. Also, the expansion of the universe decreases the rate at which we receive photons, as compared to the rate at which photons left a source, by another factor of 1+z (gravitational time dilation). Consequently, as redshift goes continuously towards infinity (cosmological horizon, not Hubble radius), intensity continuously decreases towards zero.

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Also, the expansion of the universe decreases the rate at which we receive photons, as compared to the rate at which photons left a source, by another factor of 1+z (gravitational time dilation).

Can you point me at an explanation of this effect as I would like to understand it. I have come across gravitational time dilation in association with mass but not the expansion of the universe before.

Also do you agree it fades towards a cut-off or are you saying a cut-off does not exist ?The paper I referenced implies there is one.

Thanks Andrew

George, I have managed to track down some papers on cosmological time dilation that fits your formula and some Sn Ia results that seem to confirm it. (e.g. http://www.ppd.stfc.ac.uk/ppd/resources/pdf/ppd_seminar_100609_talk_1.pdf [Broken] and my original link!!) I assume this is what you intended. Thanks

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What exactly is the cosmological horizon? And also could one just apply the typical equation for the Doppler effect to a ray of light emitted from a retreating galaxy to calculate the redshift as well as the calculation you suggested?There is a fading (and not just at and beyond the Hubble radius). The expansion of the universe has, in two ways, diminished the energy flux that we receive beyond just a distance effect. The energy of light is inversely proportional to its wavelength (energy of a photon is ##E=hc/\lambda)##. As the light travels to us, the expansion of the universe expands the wavelength of the light by a factor of 1+z, where z is redshift. Also, the expansion of the universe decreases the rate at which we receive photons, as compared to the rate at which photons left a source, by another factor of 1+z (gravitational time dilation). Consequently, as redshift goes continuously towards infinity (cosmological horizon, not Hubble radius), intensity continuously decreases towards zero.

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Simon Bridge

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Post #5 and #6 contain links you should check out since they address your questions.What exactly is the cosmological horizon? And also could one just apply the typical equation for the Doppler effect to a ray of light emitted from a retreating galaxy to calculate the redshift as well as the calculation you suggested?

Not good enough? You can also google "cosmological horizon" and get a range of articles explaining it at a variety of different levels ... you can, then, pick the one most suited to your understanding. Basically, it is the radius at which the galaxies disappear due to cosmological expansion.

The same articles will likely explain why we don't just interpret the redshift observed as a Doppler effect ... one of the side effects of doing this, for instance, would be that distant galaxies do not retreat faster than light: creating some um geometry problems.

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There is real data discussed in both the links I made above. Regards Andrew

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George Jones

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Can you point me at an explanation of this effect as I would like to understand it. I have come across gravitational time dilation in association with mass but not the expansion of the universe before.

It is an effect due to redshift, independent of the cause of the redshift, i.e., it is present for cosmological redshift, for redshift caused by a massive object, and even for redshift caused by relative motion between source and receiver in special relativity.

Imagine that observers A and B have identical watches. A sends a light signal to B that B sees redshifted, so that each photon B receives has lower energy (by the redshift factor) than each photon that A sends out.This also means that there is an observed frequency shift for all frequencies, including the rotational frequencies of the second hands of the watches for A and B. B uses one eye to watch the A's second hand and one eye to watch his own second hand. B observes the rotational period of A's second hand to be larger (again, by the redshift factor) than the period (1 minute) of his own second hand. Suppose that A's experimental set up sends out one photon for per revolution of his second hand, i.e., at the rate of 1 photon per minute according to A. B sees the A's rotational period to greater than 1 minute, so B receives photons at a rate of less (by a redshift factor) than one a minute. Putting stuff together, the energy flux received by B is reduced by two factors of redshift compared to the energy flux sent out by A.

Also do you agree it fades towards a cut-off or are you saying a cut-off does not exist ?The paper I referenced implies there is one.

Yes, this illustrated well by panel 3 in figure 1 of the paper. I hope to get back to this, and to some other points.

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bapowell

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This is incorrect. Photons emitted from galaxies with superluminal recession velocities will indeed reach earth. See the section "Superluminal recession and the Hubble sphere" here https://www.physicsforums.com/insights/inflationary-misconceptions-basics-cosmological-horizons/. The OP might find the full article of interest.As the photon moves towards Earth at ##c##, the distance between Earth and the photon is increasing at greater than ##c##, so (as long as space keeps expanding at its current rate or faster) the photon will simply get further and further away.

If the expansion of space was suddenly or gradually to stop, then that would be a different matter!

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If photons emitted from galaxies with super luminal recession velocities reach Earth then why would such galaxies apparently fade away?This is incorrect. Photons emitted from galaxies with superluminal recession velocities will indeed reach earth. See the section "Superluminal recession and the Hubble sphere" here https://www.physicsforums.com/insights/inflationary-misconceptions-basics-cosmological-horizons/. The OP might find the full article of interest.

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bapowell

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See George Jones' response #16 above regarding redshift.

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As the photon moves towards Earth at ##c##, the distance between Earth and the photon is increasing at greater than ##c##, so (as long as space keeps expanding at its current rate or faster) the photon will simply get further and further away.

If the expansion of space was suddenly or gradually to stop, then that would be a different matter!

This is incorrect. Photons emitted from galaxies with superluminal recession velocities will indeed reach earth. See the section "Superluminal recession and the Hubble sphere" here https://www.physicsforums.com/insights/inflationary-misconceptions-basics-cosmological-horizons/. The OP might find the full article of interest.

Having read your excellent Insight, I can now see that I was ... correct!

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Having read your excellent Insight, I can now see that I was ... correct!

As the photon moves towards Earth at ##c##, the distance between Earth and the photon is increasing at greater than ##c##, so (as long as space keeps expanding at its current rate or faster) the photon will simply get further and further away.

/QUOTE]

Sorry this is just not correct.

Regards Andrew

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bapowell

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Care to elaborate?Having read your excellent Insight, I can now see that I was ... correct!

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Care to elaborate?

From your insight:

"Consider a galaxy located beyond the Hubble radius at a distance dH that emits a photon towards Earth. Of course, locally this photon is traveling at c in accordance with special relativity. But, on account of the expansion, the photon is initially moving away from Earth with a speed vtot=vrec−c>0 (where positive velocities point away from Earth, in the direction of expansion.) ..."

You then go on to explain that if the expansion is decelerating, then the recession velocity will decrease and the photon will start moving towards the Earth.

Someone then asked the following question:

"So once the rate of expansion of a distant galaxy exceeds c, it will never slow to a recession velocity of less than c. So I am struggling to see how light emitted from a galaxy that is receding from us >c can ever reach us?"

To which you replied:

"When the universe is accelerating, there is an event horizon. In this case, there are indeed events (like the emission of a photon from a distant galaxy) that will never be observable by us. The misconception that snares many people is that this is also true during even decelerated expansion as long as the galaxy is receding at superluminal speeds."

I take it from this that if the rate of expansion continues to accelerate, then the photon will always be in a region of space that is receding superluminally (hence will never reach us); but if the expansion decelerates, then it may reach us, as above, subject to a more complicated calculation.

Given that I separated those two cases in my post (as underlined in post #20), I don't see my error.

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bapowell

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"We have seen that the speed of photons propagating towards us (the slope of our past light cone in the upper panel of Fig. 1) is not constant, but is rather vrec −c. Therefore light that is beyond the Hubble sphere has a total velocity away from us. How is it then that we can ever see this light? Although the photons are in the superluminal region and therefore recede from us (in proper distance), the Hubble sphere also recedes. In decelerating universes H decreases as ˙ a decreases (causing the Hubble sphere to recede).

At current conditions i.e. space expanding at it current rate and acceleration we can see galaxies beyond the Hubble sphere.

What am I missing here.

Regards Andrew

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