Recognizing a product of two 3d rotations (matrices)

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SUMMARY

This discussion focuses on the identification of 3D rotation matrices in the context of the Kondo effect in quantum dots with spin-orbit interaction. The main objective is to express the matrix H in the form H = (A·s)·(B·S), where A and B are rotation matrices. The analysis reveals that when Cx and Cz are non-zero, H cannot be directly identified as a rotation around the x, y, or z axes. It concludes that while A can equal D and B can be the identity matrix, the matrix D is not a rotation matrix unless specific conditions are met, particularly when γ = 0.

PREREQUISITES
  • Understanding of 3D rotation matrices and their properties
  • Familiarity with the Kondo effect and spin-orbit interaction
  • Knowledge of linear algebra, specifically matrix multiplication and eigenvalues
  • Basic concepts of quantum mechanics related to spin systems
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  • Research the properties of rotation matrices and their representation in 3D space
  • Explore the Kondo effect in quantum dots and its implications in condensed matter physics
  • Study the mathematical framework of eigenvalues and eigenvectors in relation to rotation matrices
  • Investigate advanced topics in spin-orbit coupling and its effects on quantum systems
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Physicists, mathematicians, and researchers working in quantum mechanics, particularly those focusing on spin systems and the Kondo effect. This discussion is also beneficial for students studying advanced linear algebra and its applications in physics.

AA1983
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Hi, I have a problem identifying some 3d rotation matrices. Actually I don't know if the result can be brought on the desired form, however it would make sense from a physics point of view. My two questions are given at the bottom.

\mathbf{s}=\left(<br /> \begin{array}{c}<br /> s_{x} \\ s_{y} \\ s_{z}<br /> \end{array} \right),\; \mathbf{S}=\left(<br /> \begin{array}{c}<br /> S_{x} \\ S_{y} \\ S_{z}<br /> \end{array} \right)

H=\left[\left(<br /> \begin{array}{ccc}<br /> 1-\left(1-C_{z}^{2}+C_{x}^{2}\right)\gamma^{2}&amp; 0 &amp; -2\gamma\left(1-C_{x}C_{z}\gamma\right) \\<br /> 0 &amp; 1-\left(1+C_{z}^{2}+C_{x}^{2}\right)\gamma^{2} &amp; 0 \\<br /> 2\gamma\left(1-C_{x}C_{z}\gamma\right)&amp; 0 &amp;<br /> 1-\left(1+C_{z}^{2}-C_{x}^{2}\right)\gamma^{2}<br /> \end{array} \right) \mathbf{s}\right]\cdot\mathbf{S}<br />

(this describes Kondo effect in a quantum dot with spin-orbit interaction)

The goal is to bring H on a the form H = \left(\mathbf{A}\mathbf{s}\right)\cdot\left(\mathbf{B}\mathbf{S}\right) where A and B are matrices describing rotations.


For Cx=Cz=0 :

H=\left[\left(1-\gamma^{2}\right)\underbrace{\left(<br /> \begin{array}{ccc}<br /> 1 &amp; 0 &amp; \theta \\<br /> 0 &amp; 1 &amp; 0 \\<br /> -\theta &amp; 0 &amp; 1<br /> \end{array} \right)}_{R_{y}(\theta)+O(\theta^{2})}<br /> \mathbf{s}\right]\cdot\mathbf{S} \;\; \approx \;\; \left(1-\gamma^{2}\right)\left(R_{y}(\theta) \mathbf{s}<br /> \right)\cdot \mathbf{S} \;, \qquad \theta=\frac{-2\gamma}{1-\gamma^{2}}<br />

That is, H is a vector product between spin S and a spin s that has been rotated around the y-axis with angle theta.

For Cx and Cz different from 0 :

In this case the matrix cannot be direct identified as a rotation around the x,y or z axis. The questions are now:

1) can it be a rotation around another axis?
2) Is it possible to write it as H = \left(\mathbf{A}\mathbf{s}\right)\cdot\left(\mathbf{B}\mathbf{S}\right) where A and B are matrices describing rotations?

I would be glad if anybody has an idea about how to deal with this.
 
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You essentially have written that H = \mathbf{s}_1^T \mathbf{D} \mathbf{s}_2, and the question is whether you can write \mathbf{D} = \mathbf{A} \mathbf{B}, where A and B are rotation matrices. Now, rotation matrices form a group, hence \mathbf{D} should also be a rotation matrix. Is \mathbf{D} orthogonal? I'm assuming it is.

Anyway, there isn't a unique way of writing D as a product of two rotations. One is to take A = D and B = identity. Maybe I've misunderstood.
 
One of the real eigenvectors of the matrix is the y unit vector, so if it is a rotation matrix it can only possibly be a rotation about the y-axis. If it is a rotation matrix, the corresponding eigenvalue
1-\left(1+C_{z}^{2}+C_{x}^{2}\right)\gamma^{2},
must be equal to 1. This can only happen if \gamma = 0. So except in this presumably trivial case, no, it is not a rotation matrix.

Dave
 
Last edited:

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