Recoil energy from neutrino question

  • Thread starter Thread starter Exulus
  • Start date Start date
  • Tags Tags
    Energy Neutrino
Click For Summary
SUMMARY

The discussion focuses on calculating the recoil energy of a Cl37 atom resulting from the decay of an Ar37 atom through electron K capture, which emits a neutrino and a gamma ray. The key values provided include a binding energy of 3 KeV, a mass difference of 816 KeV, and a known recoil energy of 9.6 eV. The user initially calculated the Q value as 813 KeV and attempted to apply linear momentum conservation principles. The solution was ultimately found by using the formula E = p²/2m, confirming that the X-ray emission did not need to be considered in the calculations.

PREREQUISITES
  • Understanding of electron K capture and its implications in nuclear decay
  • Familiarity with the concepts of binding energy and mass difference in nuclear physics
  • Knowledge of linear momentum conservation in particle physics
  • Proficiency in applying the formula E = p²/2m for kinetic energy calculations
NEXT STEPS
  • Study the principles of electron K capture in nuclear reactions
  • Learn about calculating Q values in nuclear decay processes
  • Explore momentum conservation in particle interactions
  • Review kinetic energy calculations using E = p²/2m in various contexts
USEFUL FOR

Students and professionals in nuclear physics, particularly those interested in decay processes and recoil energy calculations, as well as educators teaching related concepts in advanced physics courses.

Exulus
Messages
50
Reaction score
0
Hi guys,

I've been struggling with this problem for a while now and can't seem to get anywhere with it. Roughly speaking:

We are given that an Ar37 atom decays through electron K capture into a Cl37 atom and a neutrino, plus a gamma ray of wavelength 4.2 Angstroms. The binding energy of the K capture is 3KeV and the mass difference between Ar37 and Cl37 is 816KeV. We've been asked to calculate the recoil energy of the Cl37 atom when the neutrino is emitted. We know the answer is 9.6eV but can't seem to get anywhere near it!

So far I've calculated the Q value to be 813KeV through the mass difference minus the binding energy of the captured electron. I've tried using linear momentum conservation knowing that the energy of the neutrino is E = pc. However, I can't even see how to begin.

Can anyone offer any starters? I've tried searching everywhere :( Thanks. I believe these are all the values we need to calculate it, but i am at a loss on what to do!
 
Last edited:
Physics news on Phys.org
Hi guys (originally posted in the nuclear forum but since found this one),

I've been struggling with this problem for a while now and can't seem to get anywhere with it. Roughly speaking:

We are given that an Ar37 atom decays through electron K capture into a Cl37 atom and a neutrino, plus a gamma ray of wavelength 4.2 Angstroms. The binding energy of the K capture is 3KeV and the mass difference between Ar37 and Cl37 is 816KeV. We've been asked to calculate the recoil energy of the Cl37 atom when the neutrino is emitted. We know the answer is 9.6eV but can't seem to get anywhere near it!

So far I've calculated the Q value to be 813KeV through the mass difference minus the binding energy of the captured electron. I've tried using linear momentum conservation knowing that the energy of the neutrino is E = pc. However, I can't even see how to begin.

Can anyone offer any starters? I've tried searching everywhere :( Thanks. I believe these are all the values we need to calculate it, but i am at a loss on what to do!

[I realize this should be in a specific form but I'm literally about to go out right now, I will be back later and edit it if nessesary, thanks]
 
Have you taken the X-ray into account in your momentum conservation calculations?
 
Just want to say this has been solved now :)
 
Thanks. This has been solved now! Didn't need to take into account the x-ray emission. It was simply a case of using E = p^2/2m...doh!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
4
Views
3K
Replies
3
Views
3K
  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 38 ·
2
Replies
38
Views
6K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
979
  • · Replies 23 ·
Replies
23
Views
3K