Recombination of 2 Genes Separated by 66 Map Units

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SUMMARY

The percentage of recombination between two genes separated by 66 map units is 66%, as per the standard genetic principle that states the percentage of recombination is equivalent to the distance in centimorgans. However, the discussion highlights the importance of considering multiple crossover events, which can complicate the interpretation of recombination percentages. The participants emphasize the need for a deeper understanding of crossover events to accurately assess linkage and recombination rates. The reference to the Wikipedia article on centimorgans provides additional context for calculating recombination probabilities.

PREREQUISITES
  • Understanding of genetic linkage and recombination
  • Familiarity with centimorgans as a unit of genetic distance
  • Basic knowledge of crossover events in meiosis
  • Ability to interpret genetic equations related to recombination
NEXT STEPS
  • Study the concept of multiple crossover events in genetics
  • Learn about the calculation of recombination frequencies using genetic maps
  • Explore the relationship between centimorgans and recombination probability
  • Review case studies on gene linkage and recombination analysis
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Students in genetics, educators teaching genetic principles, and researchers analyzing gene linkage and recombination rates.

Suraj M
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Homework Statement


What is the percentage of recombination of two genes separated by 66 map units?

2. Relevant equation
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3. The Attempt at a Solution

Maybe there appears to be no linkage? I don't know, by simple substitution it would be 66%.
I don't think that's correct. I mean the book says its not 66%.
Just wanted an opinion. Thank you
 
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I haven't learned about these topics in so much detail. What we've been taught is just that (% of recombination = distance in centimorgans)
With reference to that we were given this question, how do we solve it then?
 
Did you read the link? It tells you how to do the calculation.
 
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