Rectangular Disk with Circular Hole Period Question

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JohnnyCollins
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Homework Statement


A circular disk with a rectangular hole has a radius of 0.620 m and mass of 0.470 kg. It is suspended by a point on its perimeter as shown in the figure. The moment of inertia about this point is I_p = 1.60E-1 kgm2. Its center of mass is located at a distance of s=0.120 m from the center of the circle as shown. If the disk is allowed to oscillate side to side as a pendulum, what is the period of oscillations


Homework Equations



ω=2∏f
f=1/T
I_g=1/2mr^2

The Attempt at a Solution


I'm lost on this question, any help would be greatly appreciated!
 
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Since you are stuck - go back to first principles ... start by drawing a free-body diagram for an arbitrary angular displacement and work out the torques. Fortunately you have been given the moment of inertia and the center of mass. Make an approximation for small angles and solve for T.
 
Last edited:
Simon Bridge said:
Since you are stuck - go back to first principles ... start by drawing a free-body diagram for an arbitrary angular displacement and work out the torques. Fortunately you have been given the moment of inertia and the center of mass. Make an approximation for small angles and solve for T.

So i took your advice and used the formula T=2∏√I/(mgd) and used 0.120 m for my distance, but I still ended up with the wrong answer. Am I on the right track ?
 
Simon Bridge said:
d, in your formula, is the distance from the pivot to the center of mass.
0.120m is the distance from the center of the circle to the center of mass.
spot the difference.

Got it, thanks a lot for your help!
 
No worries.

When you get stuck - go back to first principles and do a derivation.
It's amazing how naive you can be about this and still get results - just "describe the system in math and then fiddle the math" is very powerful.

In the process you may discover that you could have used a short-cut ... but having gone back over the basics deepens your understanding of the process.
Happy hacking.