(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Calculate the reflection coefficient of copper for radio waves at frequency 50Ghz and yellow light (wavelength = 0.6 micrometers)

2. Relevant equations

Reflection coefficient:R = E(r)^2/E(I)^2 = (1-n/1+n)^2

WhereE(r) is the electric intensity of the reflected wave,E(I)is the intensity of the incident wave

Also, refractive index, n, is given byn = c/v, wherevis given byfrequency x wavelength.

n = (epsilon x mu)^1/2

3. The attempt at a solution

The key variable appears to be the frequency (wavelength for the yellow light) which effects the refractive index of the copper material. My problem is linking the two together, because as stated in the above equations, I am aware of the relationship but can't pin down a definite relationship which allows me to calculate one from the other.

Any attempt to re-arrangen = c/vfails as even if i breakvdown infrequency x wavelength, i still have 2 unknowns (refractive index and wavelength (for radio waves) and frequency (for yellow light).)

Any help with this would be much appreciated, as once the refractive index is found then the first equation stated can be used.

Many thanks.

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# Homework Help: Reflection coefficient at a copper boundary

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