Reflection Grating Homework Solution

Click For Summary

Homework Help Overview

The discussion revolves around a problem related to reflection gratings in optics, specifically focusing on the calculation of angles associated with diffraction orders using the grating equation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of the grating spacing and the resulting angle for a given order of diffraction. There are questions about unit consistency and the correct order of diffraction being used. Some participants also question the appropriateness of the grating equation applied in the context of the problem.

Discussion Status

The discussion is ongoing, with participants providing insights and corrections regarding unit conversions and the application of the grating equation. There is no explicit consensus yet, as participants are exploring different interpretations and approaches to the problem.

Contextual Notes

There are indications of potential missing information regarding the angle of incidence and the specific conditions under which the grating equation is applied. Participants are also navigating the implications of using different orders of diffraction.

VVill
Messages
2
Reaction score
0

Homework Statement


http://img244.imageshack.us/img244/6852/phys24xy.png


Homework Equations


d=1/N d*sin(theta)=m*(lambda)


The Attempt at a Solution


d=1/1970
d=.0005076

.0005076*sin(theta)=2*600e-9

sin(theta)=.0000012/.0005076

arcsin(.002364)=.135º

*sigh*
 
Last edited by a moderator:
Physics news on Phys.org
One thing I see is that when you found d you didn't convert from cm to m, so you have inconsistent units in your equation.
 
d=.0005076cm = .000005076m

.000005076*sin(theta)=2*600e-9

sin(theta)=.0000012/.000005076

arcsin(.2364)=13.7º

Anything else I'm missing, because the answer is not 13.7º?
 
Why do you have m=2? If it is first order I would think it would be m=1.
 
Are you sure you are using the right equation? I think the grating equation you are using is not quite right for the conditions of your problem. The one you are using is a special case where the angle of incidence is normal to the grating. You need to include the angle of incidence in your equation. So your equation would be
d*(sin(theta(m)) - sin(theta(inc))) =m*lamda. where m = ±1 for first order maxima. Anyway see if that helps.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K