Reflection/Refraction water tank question

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SUMMARY

The discussion centers on the optical principles involved in viewing marks on a water tank, specifically using Snell's Law (n1sinθ1=n2sinθ2) to analyze light refraction at the air-water boundary. Participants confirmed that the viewer can see marks from the bottom of the tank (80 cm mark) coming up, rather than from the top (0 cm mark) going down. The key takeaway is that light rays refract at the boundary, affecting visibility based on the viewer's position relative to the water surface.

PREREQUISITES
  • Understanding of Snell's Law and light refraction
  • Basic knowledge of optics and ray diagrams
  • Familiarity with the concept of the air-water boundary
  • Ability to visualize and sketch light paths
NEXT STEPS
  • Study the principles of light refraction in different media
  • Learn how to apply Snell's Law in practical scenarios
  • Experiment with ray diagrams to visualize light paths in water
  • Research the effects of viewing angles on visibility in optical systems
USEFUL FOR

Students studying physics, particularly in optics, educators teaching light behavior, and anyone interested in practical applications of refraction in everyday scenarios.

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Homework Statement


[/B]
The 80-cm-tall, 65-cm-wide tank shown in the figure is completely filled with water. The tank has marks every 10 cm along one wall, and the 0 cm mark is barely submerged. As you stand beside the opposite wall, your eye is level with the top of the water.

Part A asked "Can you see the marks from the top of the tank (the 0 cm mark) going down, or from the bottom of the tank (the 80 cm mark) coming up?" I already answered this question: We can see the marks from the bottom of the tank coming up.

Which is the lowest or highest mark, depending on your answer to part a, that you can see?
d=__cm

I have attached an image I found online of the figure

Homework Equations



The only equation that I can think of would be Snell's Law n1sinθ1=n2sinθ2

The Attempt at a Solution



I am not sure how or where to start. If the 0 cm is at eye level, then wouldn't that be the highest mark you can see? Should I be sketching rays from each mark to the eye? If so, wouldn't they all reach the eye?
physics-drawin-png.25408.png
 
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Your idea to sketch rays from each mark to the eye is great! Just remember that your eye isn't in the water; your eye is in the air. If you'd like, you can imagine that your eye is very close to but not touching the edge (e.g. 1 mm or 1 cm). The wording in these sorts of problems can be a bit confusing at first.

Next time you're swimming in a pool, see if you can test this out.
 
Scott Redmond said:
Your idea to sketch rays from each mark to the eye is great! Just remember that your eye isn't in the water; your eye is in the air. If you'd like, you can imagine that your eye is very close to but not touching the edge (e.g. 1 mm or 1 cm). The wording in these sorts of problems can be a bit confusing at first.

Next time you're swimming in a pool, see if you can test this out.
Thank you for replying! So as the rays head toward the eye, does the incident ray hit the edge of the tank (air-water boundary?) and then refract in air before it hits the eye? Sorry, I'm still a bit lost. Wouldn't they all still hit the eye?
 
Yes, there is refraction at the air-water boundary on the horizontal surface of the water. The light then has to travel through some air -- even if it's less than 1 mm -- before it hits the eye.

Try it out with some rays, maybe starting 10 cm below the surface, and you'll see whether all of the rays hit the eye. You're correct to use Snell's law for this.
 

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